Answer:
is an example of precipitation from a solution.
Explanation:
The right answer for the question that is being asked and shown above is that: "where plants, animals, the landscape and the climate are all independent of each other." An ecosystem is a geographical area <span>where plants, animals, the landscape and the climate are all independent of each other.</span>
Keith may need some help from his manager. A customer is on the phone and she is really angry. She is threatening to post nasty comments on her blog. What should Keith say to his manager? O a) "She's angry. You deal with it." b) "So she's really angry. Her product never arrived. I think we should offer to send her a replacement product free of charge, but wanted your input." "So l'll tell her to calm down. I think she's overreacting. I doubt she'll post c) anything online." "She's really angry; she ordered the product last Wednesday, Don in customer d) service said it would arrive a week later. It was a dollhouse for her niece, Can you take it from here?"
Answer:
pH=11.
Explanation:
Hello!
In this case, since the data is not given, it is possible to use a similar problem like:
"An analytical chemist is titrating 185.0 mL of a 0.7500 M solution of ethylamine(C2HNH2) with a 0.4800 M solution of HNO3.ThepK,of ethylamine is 3.19. Calculate the pH of the base solution after the chemist has added 114.4 mL of the HNO3 solution to it"
Thus, for the reaction:
Tt is possible to compute the remaining moles of ethylamine via the following subtraction:
Thus, the concentration of ethylamine in solution is:
![[ethylamine]=\frac{0.0816mol}{0.1850L+0.1144L}=0.2725M](https://tex.z-dn.net/?f=%5Bethylamine%5D%3D%5Cfrac%7B0.0816mol%7D%7B0.1850L%2B0.1144L%7D%3D0.2725M)
Now, we can also infer that some salt is formed, and has the following concentration:
![[salt]=\frac{0.0549mol}{0.1850L+0.1144L}=0.1834M](https://tex.z-dn.net/?f=%5Bsalt%5D%3D%5Cfrac%7B0.0549mol%7D%7B0.1850L%2B0.1144L%7D%3D0.1834M)
Therefore, we can use the Henderson-Hasselbach equation to compute the resulting pOH first:
![pOH=pKb+log(\frac{[salt]}{[base]} )\\\\pOH=3.19+log(\frac{0.1834M}{0.2725M})\\\\pOH=3.0](https://tex.z-dn.net/?f=pOH%3DpKb%2Blog%28%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bbase%5D%7D%20%29%5C%5C%5C%5CpOH%3D3.19%2Blog%28%5Cfrac%7B0.1834M%7D%7B0.2725M%7D%29%5C%5C%5C%5CpOH%3D3.0)
Finally, the pH turns out to be:
NOTE: keep in mind that if you have different values, you can just change them and follow the very same process here.
Best regards!
Answer:
This is when the concentration in a solution have both the reactants and products equal.
Explanation:
An equilibrium This is when the concentration in a solution have both the reactants and products equal. It ca also be said that, equilibrium is when both the forward and reverse reactions occur at equal rates.
