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LenKa [72]
3 years ago
14

I will give 15 points please help!

Mathematics
2 answers:
N76 [4]3 years ago
6 0
It’s C good luck man(:
docker41 [41]3 years ago
4 0

Answer:

b

Step-by-step explanation:

You might be interested in
John is buying pots for the plants in his garden. The small pots are priced at m dollars each. He has already spent b dollars on
oksian1 [2.3K]

Answer:

m*x=b

Step-by-step explanation:

Price of one pot= m

Number of pots bought= x

Amount spent= b

Equation:-

m*x=b

Hope this helps.

8 0
2 years ago
A ship travels 40 miles due east, then adjusts its course 12° southward. After traveling 70 miles in that direction, how far is
Levart [38]

The ship movement is an illustration of distance and bearing

The ship is 31.97 miles from its point of departure

<h3>The distance from the point of departure?</h3>

The given parameters are:

  • Distance east = 40 milies
  • Distance southwards = 70 miles
  • Angle = 12 degrees

See attachment for the image of the above parameters

The distance (x) from the point of departure is then calculated using the following cosine function

a^2 = b^2 + c^2 - 2bc * cos(Ф)

So, we have:

x^2 = 40^2 + 70^2 - 2 * 40 * 70 * cos(12)

Evaluate the exponent and the product

x^2 = 6500 - 5477.63

Evaluate the difference

x^2 = 1022.37

Evaluate the exponent

x = 31.97

Hence, the ship is 31.97 miles from its point of departure

Read more about distance and bearing at:

brainly.com/question/24142612

8 0
2 years ago
The polynomial - 16t+ vt +s, represents the height (in feet) of an object, where v is the
Anna007 [38]

Answer:

At 1.5 seconds and 2.5 seconds

Step-by-step explanation:

Because this is parabolic motion, the object will reach the height of 68 feet when it's going up AND when it's coming down. In order to find out those times, you set the h on the left side of the equation equal to 68, because h stands for height.

Set that equal to 0 and factor to solve for t:

Using the quadratic formula, we get t = 1.5 and t = 2.5

7 0
3 years ago
For a certain population of men, 8 percent carry a certain genetic trait. For a certain population of women, 0.5 percent carry t
slavikrds [6]

Answer:

C) 150 men and 100 women

D) 200 men and 2000 women

E) 1000 men and 1000 women

Step-by-step explanation:

Hello!

To compare the proportion of people that carry certain genetic trait in men and woman from a certain population two variables of study where determined:

X₁: Number of men that carry the genetic trait.

X₁~Bi(n₁;p₁)

X₂: Number of women that carry the genetic trait.

X₂~Bi(n₂;p₂)

The parameter of interest is the difference between the population proportion of men that carry the genetic trait and the population proportion of women that carry the genetic trait, symbolically: p₁-p₂

To be able to study the difference between the population proportions you have to apply the Central Limit Theorem to approximate the distribution of both sample proportions to normal.

<u><em>Reminder:</em></u>

Be a variable with binomial distribution X~Bi(n;p), if a sample of size n is taken from the population in the study. Then the distribution of the sample proportion tends to the normal distribution with mean p and variance (pq)/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

So for both populations in the study, the sample sizes should be

n₁ ≥ 30

n₂ ≥ 30

Also:

Both samples should be independent and include at least 10 successes and 10 failures.

Both populations should be at least 20 times bigger than the samples. (This last condition is to be assumed because without prior information about the populations is impossible to verify)

  • If everything checks out then (p'₁-p'₂)≈N(p₁-p₂; p(1/n₁+1/n₂))

<u>The options are:</u>

A) 30 men and 30 women

n₁ ≥ 30 and n₂ ≥ 30

Both samples are big enough and independent.

Population 1

Successes: x₁= n₁*p₁= 30*0.08= 2.4

Failures: y₁= n₁*q₁= 30*0.92= 27.6

Population 2

Successes: x₂= n₂*p₂= 30*0.5= 15

Failures: y₂= n₂*q₂= 30*0.5= 15

The second condition is not met.

B) 125 men and 20 women

n₁ ≥ 30 but n₂ < 30

Both samples are independent but n₂ is not big enough for the approximation.

C) 150 men and 100 women

n₁ ≥ 30 and n₂ ≥ 30

Both samples are big enough and independent.

Population 1

Successes: x₁= n₁*p₁= 150*0.08= 12

Failures: y₁= n₁*q₁= 150*0.92= 138

Population 2

Successes: x₂= n₂*p₂= 100*0.5= 50

Failures: y₂= n₂*q₂= 100*0.5= 50

All conditions are met, an approximation to normal is valid.

D) 200 men and 2000 women

n₁ ≥ 30 and n₂ ≥ 30

Both samples are big enough and independent.

Population 1

Successes: x₁= n₁*p₁= 200*0.08= 16

Failures: y₁= n₁*q₁= 200*0.92= 184

Population 2

Successes: x₂= n₂*p₂= 2000*0.5= 1000

Failures: y₂= n₂*q₂= 2000*0.5= 1000

All conditions are met, an approximation to normal is valid.

E) 1000 men and 1000 women

n₁ ≥ 30 and n₂ ≥ 30

Both samples are big enough and independent.

Population 1

Successes: x₁= n₁*p₁= 1000*0.08= 80

Failures: y₁= n₁*q₁= 1000*0.92= 920

Population 2

Successes: x₂= n₂*p₂= 1000*0.5= 500

Failures: y₂= n₂*q₂= 1000*0.5= 500

All conditions are met, an approximation to normal is valid.

I hope this helps!

6 0
3 years ago
Ia-5I=5-a lojubnbobihbihbjhbjhbjhbbjhbjhbjhjvhhbkjk
Anna35 [415]

Answer:

tha

Step-by-step explanation:

4 0
3 years ago
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