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Ket [755]
2 years ago
5

On a circle of radius 10 feet, what angle would subtend an arc of length 1 feet?

Mathematics
1 answer:
Alenkasestr [34]2 years ago
6 0
\bf s=\cfrac{r\theta \pi }{180}\quad 
\begin{cases}
r=radius\\
\theta=\textit{angle in degrees}\\
s=\textit{arc's length}\\
--------------\\
r=10\\
s=1
\end{cases}
\\\\\\
1=\cfrac{10\cdot \theta\cdot \pi }{180}\impliedby \textit{solve for }\theta
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3 years ago
A company introduces a new product for which the number of units sold S is
KonstantinChe [14]
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(1/(b-a)) times the integral of f from the limits x= a to x = b. 

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The average value of S during the first year (from t = 0 months to t = 12 months) is then: 

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This equals 200/12 * (5t -9ln(2+t)) 

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708.113 units., which is the average value of S(t) during the first year. 


(b). We need to find S'(t), and then equate this with the average value. 

Now S'(t) = 1800/(t+2)^2 

So you're left with solving 1800/(t+2)^2 = 708.113 

<span>I'll leave that to you</span>
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