The answer is B, nic fiss, nic fusi
Answer:
s<p<q<r
Explanation:
Given
Element s displaces p from its oxide. Thus, s is more reactive that p
p reacts with cold water but element q cannot react with cold water. Thus,
p is more reactive than q
Element q is able to react with weak or dilute acids but element r in unable to react with weak or dilute acids. Thus, q is more reactive that r
The order of four elements on the basis of their reactivity in descending order is as follows
s<p<q<r
Aluminum oxide produced : = 79.152 g
<h3>Further explanation</h3>
Given
46.5g of Al
165.37g of MnO
Required
Aluminum oxide produced
Solution
Reaction
2 Al (s) + 3 MnO (s) → 3 Mn (s) + Al₂O₃ (s)
mol = mass : Ar
mol = 46.5 : 27
mol = 1.722
mol = 165.37 : 71
mol = 2.329
mol : coefficient ratio Al : MnO = 1.722/2 : 2.329/3 = 0.861 : 0.776
MnO as a limiting reactant(smaller ratio)
So mol Al₂O₃ based on MnO as a limiting reactant
From equation , mol Al₂O₃ :
= 1/3 x mol MnO
= 1/3 x 2.329
= 0.776
Mass Al₂O₃ (MW=102 g/mol) :
= 0.776 x 102
= 79.152 g
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Hope this helped.
