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viva [34]
3 years ago
13

In a video game, you score p game points and b triple bonus points. an expression for your score is p+3b. what is your score whe

n you earn 245 game points and 20 triple bonus points?
Mathematics
2 answers:
Simora [160]3 years ago
7 0
245+3(20)
245+60
So the final score would be 305
Nezavi [6.7K]3 years ago
6 0

Answer:

When you earn 245 game points and 20 triple bonus points your score is 305 points.

Step-by-step explanation:

First we analize the expression for the score.

The expression is p+3b

The score is a function that depends of the variables ''p'' and ''b''. Let's write the function ''score'' as S ⇒

S(p,b)=p+3b

The total game points and triple bonus points must be greater than or equal to 0 ⇒ p\geq 0\\b\geq 0

That's the domain for the function.

To find the score, we replace p=245 and b=20 in the score expression :

S(245,20)=245+3.(20)

S(245,20)=305

Therefore, your score is 305 points.

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Which ratio represents the value of sin Q
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We know that :

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From the figure, We can notice that :

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\sf{\implies sinQ = \dfrac{9}{15}}

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The manufacturer of an airport baggage scanning machine claims it can handle an average of 560 bags per hour. (a-1) At α = .05 i
ioda

Answer:

The calculated value t = 1.76 < 2.131 at 0.05 level of significance

Null hypothesis is accepted

The manufacturer’s claim is greater than 560 bags per hour

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given sample size 'n' =16

Given the manufacturer of an airport baggage scanning machine claims it can handle an average of 560 bags per hour.

mean of the Population 'μ' = 560

Mean of the sample Χ⁻ = 538

sample standard deviation' S' = 50

<em><u>Null hypothesis</u></em><em>:H₀:μ > 560</em>

<em><u>Alternative Hypothesis</u></em><em>:H₁ : :μ < 560 (left tailed test)</em>

<em>Test statistic</em>

   t = \frac{x^{-}-mean }{\frac{S}{\sqrt{n} } }

  t = \frac{538-560 }{\frac{50}{\sqrt{16} } } = -1.76

|t| = |-1.76| = 1.76

<em>Degrees of freedom </em>

<em>γ = n-1 =16-1 =15</em>

t_{\frac{\alpha }{2} } = t_{\frac{0.05}{2} } =t_{0.025} =2.131

<em><u>Conclusion</u></em>:-

The calculated value t = 1.76 < 2.131 at 0.05 level of significance

Null hypothesis is accepted

The manufacturer’s claim is greater than 560 bags per hour

6 0
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