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3 years ago

What times what equals 84

Mathematics

2 answers:

Kisachek [45]3 years ago

8 0

42 times 2 because 84 divided by 24 equals 2. Also, 84 divided by 2 equals 24.

kipiarov [429]3 years ago

4 0

Here are some
84 times 1
42 times 2
28 times 3
21 times 4
14 times 6
and 12 times 7
Your welcomes. :)

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identify the equation that does not belong with the other three. explain your reasoning. 6+x=9 | 15= x+12 | x+9 =11 | 7+x=10

Katena32 [7]

Answer is x+9=11

6+x=9
x=3

15=x+12
x=3

7+x=10
x=3

x+9=11
x=2

So x+9=11 has a different x value than the rest of the equations. So it doesn't belong with the other three.

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Lydia wanted to flip a coin and roll a die at the same time, but she also wondered what the probability of the coin landing on h

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Answer:

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Step-by-step explanation:

this is because it would be 1/2 and 1/6. you would have to multiply the bases for a probability of 1/12

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4 years ago

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3 years ago

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3 years ago

Read 2 more answers

12.what is the probability that a boy and a girl chosen randsomly will be seniors?

zhenek [66]

$\frac{\textbf{1}}{\textbf{20}}$

Step-by-step explanation:

Probability= $\frac{\text{number of favourable outcomes}}{\text{total number of outcomes}}$

Probability for a randomly chosen girl to be senior= $\frac{\text{number of senior girls}}{\text{total number of girls}}$

Probability for a randomly chosen girl to be senior= $\frac{7}{8+11+9+7}=\frac{7}{35}=\frac{1}{5}$

Probability for a randomly chosen boy to be senior= $\frac{\text{number of senior boys}}{\text{total number of boys}}$

Probability for a randomly chosen girl to be senior= $\frac{9}{10+7+10+9}=\frac{9}{36}=\frac{1}{4}$

For two independent events,

Probability for both event 1 and event 2 to take place= $\text{probability of event 1} \times \text{probability of event 2}$

Since choosing boys and girls is independent,

Probability for both boy an girl chosen to be senior= $\text{probability for boy to be senior}\times\text{probability for girl to be senior}$

Probability for both boy and girl chosen to be senior= $\frac{1}{5} \times \frac{1}{4} = \frac{1}{20}$

So,required probability is $\frac{1}{20}$

3 0

3 years ago