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3 years ago

Evaluate X-2 for x= -3

Mathematics

1 answer:

jonny [76]3 years ago

4 0

X = -3 (Given) So, x-2 = (-3) - 2 = -5

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I need help with this

gayaneshka [121]

Answer:

yes it is a function

the domain is (-3, 8]

the range looks like (-5, 2.5]

Step-by-step explanation:

using the vertical line test, you can find that it is a function

the domain is all the x values between -3 and 8. -3 is not included since there is an open circle

The range is all the y values

3 0

3 years ago

What is equivalent to (9f + 12)*4)

Natalija [7]

Answer:

Step-by-step explanation:

3 0

3 years ago

Work out the area of a circle whose diameter is equal to 14 cm.

Lera25 [3.4K]

Given:

The diameter of the circle = 14 cm

To find:

The area of the circle.

Solution:

We have,

Diameter of the circle = 14 cm

We know that the radius of the circle is half of its diameter. So,

$r=\dfrac{14}{2}$

$r=7\text{ cm}$

The area of a circle is:

$A=\pi r^2$

Substituting $\pi=\dfrac{22}{7}, r=7$ in the above formula, we get

$A=\dfrac{22}{7}\times (7)^2$

$A=22\times 7$

$A=154$

Therefore, the area of the circle is 154 square cm.

6 0

3 years ago

Pq=6x+25 and qr=16-3x; find pr

Viktor [21]

$Given:\\\overline{PQ}=6x+25\\\overline{QR}=16-3x\\\\Finding:\overline{PR}$

$If \; Q \; is \; a \; point \; in \; between \; the \; line \; segment \; \overline{PR}, \; \\ then \; the \; distance \; of \; line \; segment \; \overline{PR} \; \\ can \; be \; found \; by \; adding \; line \; segment \; \overline{PQ} \; and \; \overline{QR}.$

$Using \; the \; concept \; \overline{PQ}+\overline{QR}=\overline{PR} \;,\\ we \; need \; to \; set \; up \; an \; equation \; given \; below:$

$\overline{PR} =6x+25 +16-3x\\\\Step \; 1: Grouping \; Like \; Terms\\\overline{PR} =6x-3x+25 +16\\\\Step \; 2: Combining \; Like \; Terms\\\overline{PR} =3x+41$