Using x and y as the numbers
x+y=25 -------#1
x-y=9 -------#2
Using addition of #1 and #2
x+y+x-y= 25+9
2x+0y=34
2x=34
x=17
Using the value of x and plugging said value into #1 or #2, we can find y
x=17
x+y=25
17+y=25
y=8
OR
x-y=9
17-y=9
-y=-8
y=8
The numbers are 8 and 17
The coordinate plane is missing, so i have attached it.
Answer:
Perimeter of room = 140 ft
Area of room = 1200 sq.ft
Step-by-step explanation:
From the cordinate plane attached, we can see the polygon QRST which represents the floor plan of the roo.
Thus;
The length of the sides of the room are;
ST = RQ = 30
QT = RS = 40
Perimeter of a rectangle is the sum of all sides of the rectangle.
Thus, perimeter of the room = (30 × 2) + (40 × 2) = 140 ft
Now, area of a rectangle is the product of two perpendicular sides.
Thus area of room = 40 x 30 = 1200 sq.ft
An angle adjacent to BOC would be COD or BAC.
Answer:
Im not 100 percent sure but I think you have to do this
Step-by-step explanation:
Add all numbers together to find total students
Then add the students in Chemistry and Physics and both together
Then find what that number is in percent to the total students
The answer is 84 because 21 times 4 equals 84