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3 years ago

What happens to a substance when it becomes oxidized? reduced??

1 answer:

8 0

Oxidation is the loss of electrons. Reduction is the gain of electrons. The oxidizing agent is reduced. The reducing agent is oxidized. Cu goes from 0 to +2, it lost electrons S went from +6 to +4, it gained electrons I went from 0 to +5, it lost electrons N went from +5 to +4, it gained electrons.

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When an alkane reacts with an element from group 7a, the reaction is referred to as?

Elena-2011 [213]

Alkanes are saturated hydrocarbon, that is they contain hydrogen and carbon without a double or triple bond between the carbon atoms, e.g. ethane, propane. Group 7a in the periodic table are called halogens e.g chlorine, bromine. Alkanes react with halogens in a reaction called substitution, where halogens replace hydrogen atoms in alkanes.

7 0

3 years ago

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What is the magnetic quantum number value for an element with n = 1?

Citrus2011 [14]

Answer:

0, l is n-1 always, ml is l to -l

6 0

3 years ago

PLEASE HELP: iron reacts with nitrogen to form iron(III) nitride

lutik1710 [3]

Answer:

$2Fe +N_{2} -> 2FeN$

Explanation:

Iron is Fe, nitrogen is N. Nitrogen is diatomic, which means it occurs as a molecular pair by itself. Iron III nitride has a chemical formula of FeN because nitrogen has a charge of 3-, and iron III tells us the iron has a charge of 3+ so you just need one of each to make the charges balance and the compound neutral.

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2 years ago

Using the equation 2H2+O2=2H2O, when 47g of water are produced, how many grams of hydrogen must react?

Fed [463]

See , from the equation we can see that for forming two mole of H2O 2Mole of H2 has to react.

Mass of 2 Mole H2O is 18*2gm or 36gm.

So for forming 36 gm H2O 2×2 I.e. 4 gm H2 has to take part in reaction.

Therefore, to form 1 gm H2O 4÷36 gm of H2 has to take part.

So, for forming 47gm H2O (4÷36)×47 gm H2 has to take part

I.e. 5.22 gm of H2 has to take part

So, ans is 5.22 gm of hydrogen.

Hope it helps!!!

6 0

3 years ago

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Pls help!! plz answer correctly! will give the brainliest! Urgent!!

blagie [28]

A: Copper

B: CuO

C: $\mathrm{CuSO_4}$

D: $\mathrm{CuCO_3}$

E: $\mathrm{CO_2}$

F: $\mathrm{Cu(NO_3)_2}$

$\mathrm{CuO+ H_2SO_4}\rightarrow \mathrm{CuSO_4 + H_2O}$

$\mathrm{CuCO_3+ 2HNO_3}\rightarrow \mathrm{Cu(NO_3)_2+ CO_2+ H_2O}$

7 0

3 years ago

Read 2 more answers