Answer: 0.294 mol of
present in the reaction vessel.
Explanation:
Initial moles of
= 0.682 mole
Initial moles of
= 0.440 mole
Volume of container = 2.00 L
Initial concentration of
Initial concentration of
equilibrium concentration of
The given balanced equilibrium reaction is,

Initial conc. 0.341 M 0.220 M 0 M
At eqm. conc. (0.341-x) M (0.220-x) M (2x) M
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[HBr]^2}{[Br_2]\times [H_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BHBr%5D%5E2%7D%7B%5BBr_2%5D%5Ctimes%20%5BH_2%5D%7D)
we are given : (0.341-x) = 0.268 M
x= 0.073 M
Thus equilibrium concentration of
= (0.220-x) M = (0.220-0.073) M = 0.147 M
![[Br_2]=\frac{moles}{volume}\\0.147=\frac{xmole}{2.00L}\\\\x=0.294 mole](https://tex.z-dn.net/?f=%5BBr_2%5D%3D%5Cfrac%7Bmoles%7D%7Bvolume%7D%5C%5C0.147%3D%5Cfrac%7Bxmole%7D%7B2.00L%7D%5C%5C%5C%5Cx%3D0.294%20mole)
Thus there are 0.294 mol of
present in the reaction vessel.
Empirical Formula = C20 H60 HG1 S1 O4 (numbers should be in subscript)
Percent Composition =
MG = 43%
S = 56.8%
I think A but if it’s wrong I’m sorry ❤️
Answer:
False
Explanation:
Temperature is also heat energy, so chemical energy has no affect over it.