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2 years ago

12

Allison is analyzing the fracture pattern of a window. She sees that the fracture lines encircle the point of impact. What type

of fracture lines are
these?

1 answer:

Ray Of Light [21]2 years ago

3 0

Answer:

Concentric

Explanation:

I’m pretty sure but I’ll let you know for sure when I’m done with the test

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Using table 9.4, calculate an approximate enthalpy (in kj) for the reaction of 1.02 g gaseous methanol (ch3oh) in excess molecul

Tanya [424]

<u>Given:</u>

Mass of methanol = 1.02 g

<u>To determine:</u>

Enthalpy for the reaction of 1.02 g of methanol with excess O2

<u>Explanation:</u>

Balanced equation-

2CH3OH(g) + 3O2(g) → 2CO2(g) + 4H2O(g)

The reaction enthalpy is given as:

ΔHrxn = ∑nH°f(products) - ∑nH°f(reactants)

where n = number of moles

H°f = standard enthalpy of formation.

ΔHrxn = [2H°f(CO2(g)) + 4H°f(H2O(g))] - [2H°f(CH3OH(g)) + 3H°f(O2(g))]

= [2(-393.5) + 4(-241.8)]-[2(-201.5) + 3(0)] = -1351.2 kJ

Now, 1 mole of CH3OH = 32 g

The calculated ΔHrxn corresponds to 2 moles of CH3OH. i.e.

The enthalpy change for 64 g of Ch3OH = -1351.2 kJ

Therefore, for 1.02g gaseous methanol we have:

ΔH = 1.02 * -1351.2/64 = -21.5 kJ

Ans: The enthalpy for the given reaction is -21.5 kJ

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2 years ago

What mass of iron (III) nitrate will be in 129.8ml of a 0.3556 molar aq iron (III) nitrate solution?

Anvisha [2.4K]

<u>Answer:</u> The mass of iron (III) nitrate is 11.16 g/mol

<u>Explanation:</u>

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = 0.3556 M

Molar mass of Iron (III) nitrate = 241.86 g/mol

Volume of solution = 129.8 mL

Putting values in above equation, we get:

$0.3556M=\frac{\text{Mass of iron (III) nitrate}\times 1000}{241.86 g/mol\times 129.8}\\\\\text{Mass of iron (III) nitrate}=11.16g$

Hence, the mass of iron (III) nitrate is 11.16 g/mol

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2 years ago

I have no idea lol ...... :D

Nadusha1986 [10]

lol click other and say sumin like I dont watch the news I only watch netflix.

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2 years ago

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What is the percent yield of ferrous sulfide if the actual yield is 220.0 g and the theoretical yield is 275.6 g

Anika [276]

To get the percent yield, we will use this formula: ((Actual Yield)/(Theoretical Yield)) * 100% Values given: actual yield is 220.0 g theoretical yield is 275.6 g Now, let us substitute the values given. (220.0 grams)/(275.6 grams) = 0.7983 Then, to get the percentage, multiply the quotient by 100. 0.7983 (100) = 79.83% Among the choices, the most plausible answer is 79.8% <span>
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3 years ago

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How do you calculate the density of a gas, based on its temperature and pressure?

stiks02 [169]

We can rearrange the ideal gas equation:
PV = nRT, where n is the number of moles equivalent to:
n = mass / Mr
PV = mRT/Mr
m/V = PMr/RT
density = PMr / RT; where Mr and R are constant.

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3 years ago