X + 5 = 53 = \left[x \right] = \left[ 48\right][x]=[48]
you write out the domain and range of a function
Answer:
Quadrant 4
Step-by-step explanation:
The x value is positive so it is either in 1 or 4
The y value is negative so it is either 3 or 4
To meet both conditions, it must be 4
Step-by-step explanation:
radius of large sphere is R,
then volume is (4/3)*pie*R³
and
the radius of small sphere is r,
then volume is (4/3)*pie*r³
condition is,
volume of larger sphere is twice of the volume of smaller sphere.
then, (4/3)*pie*R³=2*(4/3)*pie*r³;
R³= 2r³
R=(2^⅓)*r
Answer:
Circumference being the distance around a circle, can be applied to any life cycle. ... At school we used a Venn Diagram which is two intersecting circles. Venn diagrams were invented by a guy John Venn as a way of picturing relationships between different groups of things.
First, think of your places. You have the ones places, tens places, hundreds places, and so on.
The first number starting from the right is the ones, and as you keep going left, the value of each given digit becomes higher.
Since 5 is in the ones place, its value would be just 5. If it were in the tens place, it would be 50. If it were in the hundreds place, it would be 500, and so on.
Think of it this way;
Ones is just one. If a number is in the 'ones' place, its value would be a single digit. If it were in the tens place, its value would be two digits.
That's how it would be for each place going left.
Every number you move to the left, its value gains a one.
So here's an example:
5555
The value of 5 in the ones place "5555" is simply 5.
In the tens place, you end up adding one zero, so the value of the second five to the left would be, "50"
So with that said, the value of the digit 5 in the number 75 is <em>5.
</em>Haha, hope this cleared up any confusion, and have a <em>wonderful </em>day! :)<em>
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