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Brut [27]
3 years ago
15

1)The metals of group 2 from top to bottom are: Be, Mg, Ca, Sr,Ba. Which if these metal will form ions most readily and why?

Chemistry
1 answer:
Pepsi [2]3 years ago
7 0

1) <em>Most ionizable atom </em>

Atomic size increases as you go down a Group (see image 1). We are adding electrons to increasingly larger shells.

The <em>valence electrons are further from the attraction of the nucleus</em>, so they are less tightly held.

Thus, Ba will form ions most readily.

2) <em>Ionization energy </em>

As an atom gets larger, the electrons are less strongly attracted to the nucleus, so it takes less energy to remove the valence electrons.

<em>Ionization energies decrease from top to bottom</em> of a Group in the Periodic Table.

Thus, in Group 2, Be has the highest ionization energy, and it decreases as you go down the Group. Ba has the lowest ionization energy.

3) <em>Ionization energy exceptions </em>

In general, ionization energies increase from left to right in a period.

However, the ionization energies of B and O are smaller than that of their immediate predecessors (see image 2).

The ionization energy of B is less than that of Be because B has a filled 2s orbital, which increases the shielding of the 2p electron and reduces the ionization energy.

The ionization energy of O is less than that of N because we are adding an extra electron to a half-filled 2p subshell.

The extra electron must go into an orbital that already contains another electron. The increased repulsion raises the energy level.

It becomes easier to remove an electron, so the ionization energy decreases.

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How many orbitals are in Phosphorus
Viefleur [7K]

Answer:

3

three half-filled orbitals each capable of forming a single covalent Bond and an additional lone - pair of electrons

8 0
2 years ago
Read 2 more answers
Someone plz plz answer this hurry plz it
ziro4ka [17]

Answer:

b

Explanation:

8 0
3 years ago
Help me please) attached the screen below. Thanks
Vitek1552 [10]

Answer:

1) d = 2.4 g/cm³

2) m = 25 g

3) v = 126.7 cm³

Explanation:

Given data:

Mass of material = 24 g

Volume of material = 10 cm³

Density of material = ?

Solution:

Formula:

d = m/v

by putting value,

d = 24 g / 10 cm³

d = 2.4 g/cm³

2) Given data:

Density of material = 5 g/cm³

Volume of material = 5 cm³

Mass of material = ?

Solution:

Formula:

d = m/v

5 g/cm³ = m / 5 cm³

m = 5 g/cm³×5 cm³

m = 25 g

3)Given data:

Density of material = 3 g/cm³

Mass of material = 380 g

Volume of material =  ?

Solution:

Formula:

d = m/v

3 g/cm³ = 380 g / v

v = 380 g /3 g/cm³

v = 126.7 cm³

7 0
3 years ago
The molar mass of I2 is 253.80 g/mol, and the molar mass of NI3 is 394.71 g/mol. How many moles of I2 will form 3.58 g of NI3?
Nat2105 [25]
To answer the problem above first we need to find the difference of molar mass of NI3 from I2, 394.71 g/mol - 253.80 g/mol = 140.91 g/mol. Knowing the molar mass of the difference of NI3 from I2, in equation mass (g) / moles (mol) = molar mass, then we substitute. 3.58g / moles = 140.91 g/mol.
moles = 3.58 / 140.91 = 0.025 moles.
6 0
3 years ago
2 points
Westkost [7]

Answer:

Law of conservation of mass

Ernest Rutherford

Explanation:

The basic law of behavior of matter that states that "mass is neither created nor destroyed in a chemical reaction or physical change".

This is the law of conservation of mass. It is very essential in understanding most chemical reaction. Also, in quantitative analysis, this law is pivotal.

Ernest Rutherford was the scientist that stated that the nucleus is made up of positive charge. It was not until James Chadwick in 1932 discovered the neutron that we had an understanding of this nuclear component.

Rutherford surmised from his experiment that because most the alpha particles passed through the thin Gold foil and just a tiny fraction was deflected back, the atom is made is made up of small nucleus that is positively charged.

4 0
3 years ago
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