Answer: Rate law is, R= 6.02[A]¹[B]²
Explanation in attached image
Answer:
115.2 °C since melting point is an intensive property
Step-by-step explanation:
The melting point of a substance does not depend on how much you have.
For example, the melting point of water is 0 °C, whether it is an ice cube from the refrigerator or in the frozen pond outside.
The freezing point of a substance is an <em>intensive property</em>.
Thus, the melting point of 100 g of sulfur is 115.2 °C because melting point in an intensive property.
Answer:
The pH of the solution will be 7.53.
Explanation:
Dissociation constant of KClO=![K_a=2.8\times 10^{-8}](https://tex.z-dn.net/?f=K_a%3D2.8%5Ctimes%2010%5E%7B-8%7D)
Concentration of acid in 1 l= 0.30 M
Then in 200 ml = ![0.30 M\times 0.200 L=0.06 M](https://tex.z-dn.net/?f=0.30%20M%5Ctimes%200.200%20L%3D0.06%20M)
The concentration of acid, HClO=[acid]= 0.006 M
Concentration of salt in 1 L = 0.20 M
Then in 300 ml = ![0.20 M\times 0.300 L=0.06 M](https://tex.z-dn.net/?f=0.20%20M%5Ctimes%200.300%20L%3D0.06%20M)
The concentration of acid, KClO=[salt]= 0.006 M
The pH of the solution will be given by formula :
![pH=pK_{a}^o+\log\frac{[salt]}{[acid]}](https://tex.z-dn.net/?f=pH%3DpK_%7Ba%7D%5Eo%2B%5Clog%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D)
![pH=-\log[2.8\times 10^{-8}]+\frac{[0.06 M]}{[0.06 M]}](https://tex.z-dn.net/?f=pH%3D-%5Clog%5B2.8%5Ctimes%2010%5E%7B-8%7D%5D%2B%5Cfrac%7B%5B0.06%20M%5D%7D%7B%5B0.06%20M%5D%7D)
The pH of the solution will be 7.53.
Yea! what the person underneath me said
Fixed density
Particles move smoothly