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zheka24 [161]
3 years ago
12

An 8.0 cm object is 40.0 cm from a concave mirror that has a focal length of 10.0 cm. Its image is 16.0 cm in front of the mirro

r.
Physics
1 answer:
svet-max [94.6K]3 years ago
6 0
 We can rearrange the mirror equation before plugging our values in. 
1/p = 1/f - 1/q. 
1/p = 1/10cm - 1/40cm
1/p = 4/40cm - 1/40cm = 3/40cm
40cm=3p  <-- cross multiplication
13.33cm = p

Now that we have the value of p, we can plug it into the magnification equation.

M=-16/13.33=1.2
1.2=h'/8cm
9.6=h'

So the height of the image produced by the mirror is 9.6cm.
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My name is Ann [436]

Answer:

(a) The convex mirror image, is always upright at all positions, while images formed by concave mirrors are always inverted when the object distance from the mirror is more than the mirrors focal length.

(b) An upright image is not seen for object at a distance from a concave mirror further than the focal length of the mirror, which is the spoon in the question

Therefore, the location of her eyes of approximately, 30 cm,  from the mirror is more than the mirror's focal length

Explanation:

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A race car starts from rest and travels east along a straight and level track. For the first 5.0 s of the car’s motion, the east
Marrrta [24]

Answer:

ax = 6.43m/s²

Explanation:

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So the first step is to calculate the time at which the velocity =12.0m/s and with this time calculate the acceleration. Detailed solution can be found in the attachment below.

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A child pulls a sled up a snow covered hill. If the child does 504J of work on the sled while pulling the sled 23m up the hill t
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lys-0071 [83]

Maybe this will help you out:

Momentum is calculate by the formula:

P = mv

Where:

P = momentum

m = mass      

v = velocity

The SI unit:

mass = kg\\ velocity = \dfrac{m}{s}

So the unit of momentum would be:

kg.\dfrac{m}{s}

Impulse is defined as the change in momentum or how much force changes momentum. It can be calculate with the formula:

I = FΔt

where:

I = impulse

F = Force

Δt = change in time

The SI unit:

F = Newtons (N) or kg.\dfrac{m}{s^{2} }

t = Seconds (s)

So the unit of impulse would be derived this way:

I = FΔt

I = kg.\dfrac{m}{s^{2} } x s

or

\dfrac{kg.m.s}{s^{2}} = \dfrac{kg.m.s}{s.s}

You can then cancel out one s each from the numerator and denominator and you'll be left with:

kg.\dfrac{m}{s}

So then:

Momentum:                             Impulse

kg.\dfrac{m}{s}                                       kg.\dfrac{m}{s}

4 0
3 years ago
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