Answer: glycogen is insoluble in water
Explanation:
Glycogen is a better storage of glucose because Glycogen is insoluble in water thus, because of the glycosidic linkages. Storing glucose as glycogen will not upset the osmotic pressure rather than glucose which is soluble in water and if it is stored as glucose it will disturb the osmotic pressure making the solution hypertonic that will cause the cell to lyse.
The glucose from glycogen is readily mobilized and is therefore a good source of energy when needed rather than free floating glucose
My 2 cents below, I tried to think through the other ones:
A. Yes, because an amino acid change has occurred.
(A gene mutation occurred, not an amino acid change)
B. Yes, because all mutations change the resulting protein.
(Sounds correct. Gene -> mRNA -> protein)
C. No, because the amino acid sequence has not been changed.
(The gene mutation means the amino acid sequence <em>has</em> changed)
D. No, because mutations in the DNA do not affect the mRNA sequence.
(They do so)
Answer:
The first anticodon leaves the ribosome through the E-site
Explanation:
Translation is the second stage of gene expression. It occurs in the ribosomes (organnelles of protein synthesis) where amino acid sequence is synthesized using a mRNA template. The tRNA (transfer RNA) is responsible for reading the mRNA codon using its ANTICODON, which is complementary to the mRNA codon.
The tRNA reads the mRNA codon and carries the amino acid that corresponds what it reads. tRNA has three binding sites on the ribosome; A-site, P-site and E-site. A tRNA molecule with the complementary anticodon binds to the codon on the P-site, and carries its corresponding amino acid. Another tRNA with complementary anticodon occupies the A-site, carrying the corresponding amino acid again.
Once both sites are occupied, the tRNA on the P-site transfers its amino acid to the one on the A-site to form a peptide bond. This causes the ribosome to shift the tRNA on the P-site, allowing the one on the A-site to be free. When this happens, the anticodon of the first tRNA on the P-site leaves the ribosome via the E-site in order to bind to another complementary mRNA codon and continue the translation process.
D. Homozygous dominant because the dad has the dominant allele.
Answer:
The perecentage of guanine is 30%
Explanation:
the DNA from any cell of all organisms should have a 1:1 ratio (base Pair Rule) of purine bases [for the DNA cytosine, thymine and for the RNA uracil] and pyrimidine bases [guanine and adenine for RNA and DNA]. The amount of guanine should be equaled to cytosine and the amount of adenine should be equaled to thymine. You can follow this rule in both strands of the DNA.
