What are three different ways to write 15,638

Mathematics

2 answers:

lukranit [14]3 years ago

7 0

1. fifteen thousand six hundred thirty eight.

Mandarinka [93]3 years ago

7 0

15638/1000 reduced is 7819/500

You might be interested in

Fraccion de 2/3+1/5=

Ksju [112]

Answer:

13/5

Step-by-step explanation:

$\frac{2}{3 } + \frac{1}{5} \\ we \: take \: \\ the \:lcd \\ \frac{(2 \times 5) + (1 \times 3)}{3 \times 5} \\ \frac{10 +3}{15} \\ \frac{13}{5}$

7 0

3 years ago

Read 2 more answers

Four expressions are shown below:

Alina [70]

The answer is A and C, because 4(7x + 2 + x) simplifies to 32x + 8, and expressions A and C also simplify to 32x + 8. I hope this helps!

8 0

3 years ago

I need you to answer with a, b, c, d

solong [7]

To find the zeros of a quadratic fiunction given the equation you can use the next quadratic formula after equal the function to 0:

$\begin{gathered} ax^2+bx+c=0 \\ \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}$

For the given function:

$f(x)=2x^2-10x-3$ $x=\frac{-(-10)\pm\sqrt[]{(-10)^2-4(2)(-3)}}{2(2)}$ $x=\frac{10\pm\sqrt[]{100+24}}{4}$ $\begin{gathered} x=\frac{10\pm\sqrt[]{124}}{4} \\ \\ x=\frac{10\pm\sqrt[]{2\cdot2\cdot31}}{4} \\ \\ x=\frac{10\pm\sqrt[]{2^2\cdot31}}{4} \\ \\ x=\frac{10\pm2\sqrt[]{31}}{4} \\ \end{gathered}$ $\begin{gathered} x_1=\frac{10}{4}+\frac{2\sqrt[]{31}}{4} \\ \\ x_1=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \end{gathered}$ $\begin{gathered} x_2=\frac{10}{4}-\frac{2\sqrt[]{31}}{4} \\ \\ x_2=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}$

Then, the zeros of the given quadratic function are: