This is something very complex to explain and your diagram isn't shown so it really depends on what it looks like before Anyone will be able to answer this question. If you will post the diagram I will help you to the best of my ability.
Answer: 99.64 nm (≅ 100 nm)
Explanation: In order to explain this problem we have to obtain destructive inteference from two waves that reflect in the film and lens surface so both waves have a λ/2 shift then we have to get a difference path (2L) equal to an odd number of the half wavelegth.
Then we have the following expression:
L=(m+1/2)* λ/(2*n2); where n2 is the refractive index of the coating
for m=0 we have the minimum thickness for the coating
L=λ/(4*n2)=99.64 nm (≅ 100 nm)
Answer:
Explanation:
To determine the <u>muzzle velocity of the gun</u>, we must know how long does it take the ball to <u><em>strikes the ground </em></u>
Since the ground is at y=0 and
Solving for t
Now, to determine the muzzle velocity we need to find its acceleration first
(1)
(2)
If we analyze the final velocity is 0. From (2) we have that
(3)
Replacing (3) in (1)
Solving (3)
Answer:
The velocity at that time would be . The velocity of this particle is continuously changing.
Explanation:
Differentiate the expression for position with respect to time to find an expression for velocity.
.
Hence, at , velocity would be .
Since velocity changes with time , the velocity of this particle is continuously changing.
KE = 1/2mv²
= 1/2(100)(4.0²)
KE = 800 J
hope this helps :)