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2 years ago

What action within the heart creates the characteristic “lib-dub” heartbeat?

Physics

2 answers:

harkovskaia [24]2 years ago

8 0

Valves of the heart oppening and closing

balu736 [363]2 years ago

8 0

A heartbeat is the sound caused by the heart valves opening and closing while they pump blood. A properly working heart only has blood flowing in one direction. This is possible by the valves opening and closing in exact coordination with the heart’s pumping action. Assuming you meant lub-dub, the lub sound is the tricuspid and mitral valves closing. The dub sound is the aortic and pulmonary valves closing. Combined, they make the sound of a heartbeat/the sound of someone's heart working properly.

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A metal ring 4.30 cm in diameter is placed between the north and south poles of large magnets with the plane of its area perpend

CaHeK987 [17]

Answer:

A)0.00966 N/C

B) counterclockwise direction

Explanation:

We are given;

Diameter of the metal ring; d = 4.3 cm

Radius;r = 2.15 cm = 0.021- m

Initial magnetic field, B = 1.12 T

Rate of decrease of the magnetic field;dB/dt = 0.23 T/s

Now, as a result of change in magnetic field, an emf will be induced in it. Thus, , electric field is induced and given by the formula :

∫E•dr = d/dt∫B.A •dA

This gives;

E(2πr) = dB/dt(πr²)

Gives;. 2E = dB/dt(r)

E = dB/dt × 2r

We are given;

E = 0.23 × 2(0.021)

E = 0.00966 N/C

The magnitude of the electric field induced in the ring has a magnitude of 0.00966 N/C

B) The direction of electric field will be in a counterclock wise direction when viewed by someone on the south pole of the magnet

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2 years ago

a 1 kg emery stone measuring 20 cm redium, is rotating with an angular speed of 39 revolutions per minute, when the motor is tur

musickatia [10]

Answer: 13,24

Explanation:

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2 years ago

En un experimento de calorimetría, 0.50 kg de un metal a 100°C se añaden a 0.50 kg de agua a 20°C en un vaso de calorímetro de a

Maru [420]

Answer:

c=0.14J/gC

Explanation:

2) The specific heat will be the same because it is a property of the substance and does not depend on the medium.

We can use the expression for heat transmission

$Q=mc(T_2-T_1)$

In this case the heat given by the metal (which is at a higher temperature) is equal to that gained by the water, that is to say

$Q_1=-Q_2$

for water we have to

c = 4.18J / g ° C

replacing we have

$c_{metal}*(500g)(100\°C-25\°C)=-(250g)(4.18\frac{J}{g\°C})(20\°C-25\°C)\\c_{metal}=0.14\frac{J}{g\°C}$

I hope this is useful for you

2) El calor específico será igual porque es una propiedad de la sustancia y no depende del medio.

Podemos usar la expresión para la transmisión de calor

$Q=mc(T_2-T_1)$

En este caso el calor cedido por el metal (que está a mayor temperatura) es igual al ganado por el agua, es decir

$Q_1=-Q_2$

para el agua tenemos que

c=4.18J/g°C

reemplazando tenemos

$c_{metal}*(500g)(100\°C-25\°C)=-(250g)(4.18\frac{J}{g\°C})(20\°C-25\°C)\\c_{metal}=0.14\frac{J}{g\°C}$

7 0

2 years ago

A motorcycle skids for a distance of 2.0 m with the icy road pushing on its tires with force of 120 N as its

AnnyKZ [126]

Answer:

-240

Explanation:

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2 years ago

How many different types of atoms are present in one molecule of aluminum hydroxide, Al(OH)3?

tatyana61 [14]

There are approximately 3 different types of atoms that are present in one molecule of aluminum hydroxide, AI(OH)3.

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2 years ago

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