Answer:
This zygote is tetraploid.
Explanation:
An haploid cell contains a single set of chromosomes (one chromosome 1, one chromosome 2, one chromosome 3, etc.).
A diploid cell contains two sets of chromosomes (two chromosomes 1, two chromosomes 2, etc.).
Usually, two haploid gametes fuse and generate a diploid zygote, that has a set of chromosome from one parent and another set from the other parent.
If during meiosis the generated gametes are diploid instead of haploid, the resulting zygote from that fusion will have four copies of each chromosome. An organism that has four sets of chromosomes (four chromosomes 1, four chromosomes 2, etc.) is called tetraploid.
Antibiotic resistance is a consequence of evolution via natural selection. The antibiotic action is an environmental pressure; those bacteria which have a mutation allowing them to survive will live on to reproduce. They will then pass this trait to their offspring, which will be a fully resistant generation.
Option(a) Monera is the correct answer.
In the obsolete five-kingdom system, prokaryotes were included within Monera group.
<h3>What are prokaryotes?</h3>
- Prokaryotes are creatures without a nucleus or other organelles in their cells.
- Bacteria and archaea, two separate groupings of prokaryotes with allegedly independent evolutionary histories, are separated into.
- The majority of prokaryotes are tiny, single-celled creatures with a straightforward structure.
<h3>The definition of Monera:</h3>
- the prokaryotic kingdom that includes bacteria, reproduces primarily asexually by budding or fission, and obtains its nutrition through photosynthesis or chemosynthesis.
<h3>What are five Monera examples?</h3>
- <u>Cyanobacteria</u>, which are blue-green algae
- <u>Streptococcus</u>, which are cocci-shaped bacteria
- <u> E</u>. <u>Coli</u>
- <u>Vibrio</u> <u>cholerae</u> (cholera)
- <u>Treponema</u> <u>pallidum</u> (syphilis)
- other bacteria with a spiral form.
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The provided question is incomplete as the group of choices were not given, however, the choices as follows:
A. (a > b) and (a > c)
B. (a > b) and (a < c)
C. (a < b) and (a > c)
D. (a < b) and (a < c)
E. (a > b) and (b > c)
Answer:
The correct answer is - D. (a < b) and (a < c)
Explanation:
The persistent length of actin filaments, a bundle of cross-linked actin filaments and microtubules can be compared on their typical persistent length.
The persistent length of actin filaments is 15 µm. And due to the crosslink with one another to make a bundle their length reduced As the actin filaments cross-link each other their persistent length will be reduced. however, it is still longer than single actin filament around 20 nm.
The persistent length of microtubules is 6mm.
So b > a, a < b and a < c.
So fourth option a < c and b > a is the correct answer.