Identify the folded membranes that move materials around the cell
1 answer:
You might be interested in
Answer : 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.
Solution : Given,
Mass of Cu = 300 g
Molar mass of Cu = 63.546 g/mole
Molar mass of = 183.511 g/mole
- First we have to calculate the moles of Cu.
The moles of Cu = 4.7209 moles
From the given chemical formula, we conclude that the each mole of compound contain one mole of Cu.
So, The moles of Cu = Moles of = 4.4209 moles
- Now we have to calculate the mass of
.
Mass of = Moles of
× Molar mass of
= 4.4209 moles × 183.511 g/mole = 866.337 g
Mass of = 866.337 g = 0.8663 Kg (1 Kg = 1000 g)
Therefore, 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.
Answer:
<h3>The answer is 30 cm³</h3>Explanation:
The volume of a substance when given the density and mass can be found by using the formula
From the question
mass = 180 g
density = 6 g/cm³
We have
We have the final answer as
<h3>30 cm³</h3>Hope this helps you