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spin [16.1K]
3 years ago
12

Do you know the answer if so pls answer

Chemistry
1 answer:
igomit [66]3 years ago
6 0

Answer:

They are both pretty soft for metals, but magnesium is significantly harder than calcium using this scale . Mg = 2.5, Ca = 1.75. The larger the number, the harder

Explanation:

You might be interested in
What is the molecule shown below?
arsen [322]

Answer:

2,3 -Dimethyl pentane

Explanation:

The given molecule is 2,3-Dimethyl pentane.

First of all select the longest chain of C-C atom. This will be the parent name.

In given structure the longest chain is straight chain that contain five carbon. Thus the parent name will pentane and there is no double or triple bond the given structure is of alkane.

Than locate the positions of functional groups attached.

In given structure there are two methyl groups are present. Give the name in such a way that functional groups will have lowest number. In given case we will start from the left.

The first methyl group will have number 2 and second will have number 3.

The name will be,

2,3-Dimethyl pentane

8 0
3 years ago
Fill in the blanks in the picture. Provide Explanation.
kogti [31]

Answer:

3 Protons .

3 NEUTEON

1 ELECTRONS .

1 ELECTRONS.

1 ELECTRONS.

1 ELECTRONS.

1 ELECTRONS.

5 ELECTRONS

4 0
3 years ago
How much heat is needed to raise the temperature of 2g of glass from 20°C to 30°C?
lakkis [162]

Answer:

‏‏‎ ‎     ‏‏‎ ‎

Explanation:

 

6 0
3 years ago
What is the number of molecules present in 1.12 dm^3 of nitrogen gas at STP​
Anuta_ua [19.1K]

Answer:

\huge\boxed{\sf No.\ of\ molecules = 3 * 10\²\² \ molecules}

Explanation:

<u>Given Data:</u>

Volume = v = 1.12 dm³ = 1.12 L

Density of nitrogen at STP = D = 1.25 g / L

Molar mass = M = 14 * 2 = 28 g / mol

Avogadro's Number = \tt{N_{A}} = 6.023 * 10²³ mol⁻¹

<u>Required:</u>

No. of molecules = ?

<u>Formula:</u>

\tt{No. \ of \ molecules = \frac{Density * Volume}{Molar\ Mass} * N_{A}}

<u>Solution:</u>

No. of molecules = (1.25*1.12) / 28 * (6.023 * 10²³)

No. of molecules = ( 1.4 / 28 ) * 6.023 * 10²³

No. of molecules = 0.05 * 6.023 * 10²³

No. of molecules = 0.3 * 10²³

No. of molecules = 3 * 10²² molecules

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
4 0
3 years ago
Volume in liters of carbon dioxide produced at stp when 0.85 grams of butane reacts
MAVERICK [17]

Volume in liters of Carbon dioxide : 0.672

<h3>Further explanation</h3>

Reaction(combustion of butane-C₄H₁₀)

2C₄H₁₀+13O₂⇒8CO₂+10H₂O

mol butane (MW=58,12 g/mol) :

\tt \dfrac{0.85}{58,12}=0.015

mol CO₂ : mol C₄H₁₀ = 8 : 4, so mol CO₂ :

\tt \dfrac{8}{4}\times 0.015=0.03

At STP, 1 mol = 22.4 L, so volume CO₂ :

\tt 0.03\times 22.4~L=0.672~L

3 0
3 years ago
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