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3 years ago

14

What would happen if you tried to sqeeze a gas into a smaller container?

1 answer:

kolbaska11 [484]3 years ago

8 0

It won't happen because the force of the particles will prevent you from doing it

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Which compound is covalently bonded? <br> Select one: <br> a. Al2O3 b. Fe2O3 c. SO2 d. CuCl2

azamat

Answer:

The answer is D-CuCl2

I hope this helps

7 0

3 years ago

Read 2 more answers

Why does a pan of warm water eventually become the same temperature as the room it is in

rewona [7]

the room will either cool down or warm up the water until it is the same temperature as the room around it.

4 0

3 years ago

What is the h+ concentration for an aqueous solution with poh = 3.35 at 25 ∘c? express your answer to two significant figures an

RSB [31]

POH value was calculated by the negative logarithm of hydroxide ion concentration.
To know the hydrogen ion concentration, we need to know the pH value, that can be found out if pOH is known
pH + pOH = 14
pH = 14 - pOH
pH = 10.65
once the pH is known we have to find the antilog.
[H⁺] = antilog (-pH)
antilog can be found by
[H⁺] = 10^(-10.65)
[H⁺] = 2.2 x 10⁻¹¹ M

3 0

3 years ago

A tank with volume of 2.4 cu ft is filled with Methane to a pressure of 1500 psia at 104 degrees F. Determine the molecular weig

Soloha48 [4]

Explanation:

It is known that equation for ideal gas is as follows.

PV = nRT

The given data is as follows.

Pressure, P = 1500 psia, Temperature, T = $104^{o}F$ = 104 + 460 = 564 R

Volume, V = 2.4 cubic ft, R = 10.73 $psia ft^{3}/lb mol R$

Also, we know that number of moles is equal to mass divided by molar mass of the gas.

n = $\frac{mass}{\text{molar mass}}$

m = $n \times W$

= $0.594 \times 16.04$

= 9.54 lb

Hence, molecular weight of the gas is 9.54 lb.

We will calculate the density as follows.

d = $\frac{PM}{RT}$

= $\frac{1500 \times 16.04}{10.73 \times 564}$

= 3.975 $lb/ft^{3}$

Now, calculate the specific gravity of the gas as follows.

Specific gravity relative to air = $\frac{\text{density of methane}}{\text{density of air}}$

= $\frac{3.975 lb/ft^{3}}{0.0765 lb/ft^{3}}$

= 51.96

6 0

3 years ago

An experiment shows that a 250 −mL gas sample has a mass of 0.436 g at a pressure of 742 mmHg and a temperature of 27 ∘C.

icang [17]

Answer:

41.9 g/ mol hope that helps you out

Explanation:

d=p.m/ r.t

8 0

3 years ago