Question

Which Is the equation of a circle with a radius of 2 and it's center at (-4,3)?

Answer 1

(x - xc)² + (y - yc)² = r²

Where xc and yc are center coordinates

(x - (-4))² + (y - 3)² = 2²

$(x + 4)^2 + (y - 3)^2 = 4$

x² + 2.x.4 + 4² + y² - 2.y.3 + 3² = 4

x² + 8x + 16 + y² - 6y + 9 = 4

x² + y² + 8x - 6y + 25 - 4 = 0

x² + y² + 8x - 6y + 21 = 0