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Nuetrik [128]
3 years ago
13

What happens at the end of most cold currents?​

Physics
2 answers:
Akimi4 [234]3 years ago
5 0

Answer:

Ocean currents act as conveyer belts of warm and cold water, sending heat toward the polar regions and helping tropical areas cool off, thus influencing both weather and climate.

Explanation:

blondinia [14]3 years ago
5 0

If ocean currents were to stop, climate could change quite significantly, particularly in Europe and countries in the North Atlantic. In these countries, temperatures would drop, affecting humans as well as plants and animals. In turn, economies could also be affected, particularly those that involve agriculture.
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Which of the following is incorrect for nuclear forces
densk [106]

Answer:

c they obey inverse square law

4 0
3 years ago
Read 2 more answers
Newton’s law of universal gravitation states that the force of gravity
trapecia [35]
All of the above as it states that "<span>a particle attracts every other particle in the universe using a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers"</span>
8 0
3 years ago
A 40.0 kg wagon is towed up a hill inclined at 18.5 degrees with respect to the horizontal. The tow rope is parallel to the incl
sp2606 [1]

Answer:

7.9m/s

Explanation:

We are given that

Mass of wagon=40 kg

\theta=18.5^{\circ}

Tension=140 N

Initial velocity of wagon=u=0

Displacement=s=80 m

Net force applied  on wagon=F=T-mgsin\theta=140-40(9.8)sin18.5=15.7 N

By using g=9.8m/s^2

a=\frac{F}{a}=\frac{15.7}{40}=0.39m/s^2

We know that

v^2-u^2=2as

Using the formula

v^2=2\times 0.39\times 80

v=\sqrt{2\times 0.39\times 80}=7.9m/s

5 0
3 years ago
rickey approaches third base. He dives head first, hitting the ground at 6.75 m/s and reaching the base at 5.91 m/s in 2.5 secon
Gekata [30.6K]

Answer:

15.825 m

Explanation:

t = Time taken = 2.5 s

u = Initial velocity = 6.75 m/s

v = Final velocity = 5.91 m/s

s = Displacement

a = Acceleration

Equation of motion

v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{5.91-6.75}{2.5}\\\Rightarrow a=-0.336\ m/s^2

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{5.91^2-6.75^2}{2\times -0.336}\\\Rightarrow s=15.825\ m

The distance Rickey slides across the ground before touching the base is 15.825 m

4 0
3 years ago
What is the mass of a 100-N crate of delicious candy
Svetach [21]

Answer:

Explanation:

weight ( w ) = 100 N

mass (m) = ?

WE know

g = 10 m/s²

w = m * g

or

m = w / g

m = 100 / 10

m = 10 kg

hope it will help :)

6 0
3 years ago
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