Question

A stone was dropped off a cliff and hit the ground with a speed of 136 ft/s. what is the height of the cliff? (use 32 ft/s2 for the acceleration due to gravity.)

Answer 1

(v1)^2=(v0)^2-2ad; v1= final velocity; v0= initial velocity; a=gravitational constant;d=distance Since the stone was dropped we know v0=0. (v1)^2=2ad (136)^2=2(32)d d=(136)^2/(2*32) d=289ft