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3 years ago

Write an equation of the line satisfying the given conditions. Through (1,−5); parallel to 5x=6y+7

Mathematics

1 answer:

evablogger [386]3 years ago

6 0

Answer:

y = 5/6 x - 35/6

Step-by-step explanation:

first convert equation to y = mx + b to get the slope

5x -7 = 6y

5/6 x - 7/6 = y

5/6 is the slope

because the line is parallel, the slope is 5/6

use the point given and simplify

y + 5 = 5/6 (x - 1)

y + 5 = 5/6x - 5/6

y = 5/6x - 5/6 - 30/6

y = 5/6x - 35/6

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3 years ago

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I will do Point A carefully, The others I will indicate. Start with the Given Point A. Then do the translations

A(-1,2) Original Point

Reflection: about x axis:x stays the same; y becomes -y:Result(-1,-2)

T<-3,4>: x goes three left, y goes 4 up (-1 - 3, -2 + 4): Result(-4,2)

R90 CCW: Point (x,y) becomes (-y , x ) So (-4,2) becomes(-2, - 4): Result (-2, - 4)

B(4,2) Original Point

Reflection: (4, - 2)
T< (-3,4): (4-3,-2 + 4): (1 , 2)
R90 CCW: (-y,x) = (-2 , 1)

C(4, -5) Original Point

Reflection (4,5)
T<-3,4): (4 - 3, 5 + 4): (1,9)
R90, CCW (-9 , 1)

D(-1 , -5) Original Point

Reflection (-1,5)
T(<-3,4): (-1 - 3, 5 + 4): (-4,9)
R90, CCW ( - 9, - 4)

Note: CCW means Counter Clockwise

The graph on the left is the same one you have been given.

The graph on the right is the same figure after all the transformations

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