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Vikki [24]
3 years ago
14

Write an equation of the line satisfying the given conditions. Through (1,−5); parallel to 5x=6y+7

Mathematics
1 answer:
evablogger [386]3 years ago
6 0

Answer:

y = 5/6 x - 35/6

Step-by-step explanation:

first convert equation to y = mx + b to get the slope

5x -7 = 6y

5/6 x - 7/6 = y

5/6 is the slope

because the line is parallel, the slope is 5/6

use the point given and simplify

y + 5 = 5/6 (x - 1)

y + 5 = 5/6x - 5/6

y = 5/6x - 5/6 - 30/6

y = 5/6x - 35/6

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What is the solution to the inequality |2n+5|>1?
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ANSWER

n <  - 3 \: or \: n>  - 2



EXPLANATION



The given inequality is,

|2n + 5|  \:  >  \: 1


By the definition of absolute value,



- (2n + 5)  \:  >  \: 1 \: or \: (2n + 5) \:  >  \: 1



We divide through by negative 1, in the first part of the inequality and reverse the sign to get,

2n + 5 \:   <   \:  - 1 \: or \: (2n + 5) \:  >  \: 1

We simplify now to get,

2n   \:   <   \:  - 1 - 5 \: or \: 2n  \:  >  \: 1 - 5


2n   \:   <   \:  - 6 \: or \: 2n  \:  >  \:  - 4


Divide through by 2 to obtain,

n   \:   <   \:  - 3 \: or \: n  \:  >  \:  - 2


4 0
3 years ago
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Given that y = 18 + 3x²<br> i) express x in terms of y
fgiga [73]

Answer:

\sqrt{-6 + \frac{y}{3}} = x

Step-by-step explanation:

y = 18 + 3x²

- 18 - 18

__________

\frac{-18 + y}{3} = \frac{3x^2}{3} \\ \\ -6 + \frac{y}{3} = x^2 \\ \\ \sqrt{-6 + \frac{y}{3}} = x

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6 0
3 years ago
What is the measure in radians for the central angle of a circle whose radius is 8 cm and intercepted arc length is 7.2 cm? Ente
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The measure in radians for the central angle of the circle is; 0.9 radians.

<h3>What is the angle measure in radians of the central angle?</h3>

Since, the length of the arc is given as 7.2cm and it's radius is 8cm.

It follows that the angle measure of the central angle can be evaluated as follows;

7.2 = (A/6.28) × 2× 3.14 × 8

7.2 = 8A

A = 7.2/8

A = 0.9 radians.

Read more on radian measure;

brainly.com/question/19758686

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2 years ago
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Answer:

Step-by-step explanation:

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2 years ago
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Did I do these two correctly?
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