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Simora [160]
3 years ago
10

Cl2(g) + 2kbr(aq)= 2kcl(aq) + Br2(I)

Chemistry
1 answer:
kotegsom [21]3 years ago
8 0
Good the equation is balanced already
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Which is produced when minerals are mixed with water and decaying plants and animals?<br> rack
vazorg [7]

Answer:

Soil is a mix of inorganic minerals, water, air, organic matter from dead and decaying plants and animals, and an incredible array of living organisms, ranging in size from microscopic bacteria and fungi to earthworms, moles, and shrews.

Explanation:

hope this helps.

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7 0
3 years ago
Gasoline has a density of 0.749 g/mL. How many pounds does 19.2 gallons of gasoline weigh? Use significant figures. Do not enter
Yanka [14]
In this question, you are given the gasoline density (0.749g/ml) and volume of the gasoline (19.2 gallons). You are asked the mass of the gasoline in pounds. Then you need to change the grams into pounds and the ml into gallons. The calculation would be:

mass of gasoline= density * volume
mass of gasoline=  0.749g/ml * (1 pound/453.592grams) * 3785.41ml/gallon * 19.2 gallon= 120 pounds

7 0
3 years ago
How many moles of Mg are present in 62.23 grams of Mg? (Show your calculations for full credit.)
mylen [45]
62.23 = 1512.5001499999998 moles
5 0
3 years ago
Mention the four characterstics of warm blooded animals.<br>​
Igoryamba

Answer:

The four characrteristics of warm blooded animals are÷

Explanation:

i=They can keep its body temperature the same no matter what the outside temperature .

ii=They can maintain a constant body temperature.

iii=They obtain energy from food consumption.

iv=They maintain their body temperature higher than environment.

7 0
3 years ago
Read 2 more answers
Propanoic acid, ch3ch2cooh, has a pka =4.9. draw the structure of the conjugate base of propanoic acid and give the ph above whi
xenn [34]

Conjugate base of Propanoic acid (CH_{3}CH_{2}COOH is propanoate where -COOH group gets converted to -COO^{1-}. The structure of conjugate base of Propanoic acid is shown in the diagram.

The p^{H} above which 90% of the compound will be in this conjugate base form can be determined using Henderson's equation as propanoic acid is weak acid and it can form buffer solution on reaction with strong base.

p^{H}= p^{k_{a}+ log\frac{[Conjugate base]}{[acid]}=4.9+log\frac{90}{10}=5.85

As 90% conjugate base is present, so propanoic acid present 10%.

8 0
3 years ago
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