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olya-2409 [2.1K]
3 years ago
7

2CO + O2 --> 2002

Chemistry
1 answer:
olga_2 [115]3 years ago
4 0
8 moles I think I’m not sure
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Which formulas represent two polar molecules?
sergeinik [125]

Answer is: 3) H2O and HCl.

Polar molecules are water (H₂O) and hydrochloric acid (HCl).

Nonpolar molecules are carbon(IV) oxide (CO₂) and methane (CH₄).

Carbon(IV) oxide is nonpolar because CO₂ is linear molecule and the oxygen atoms are symmetrical (bond angles 180°).

Water is polar because of the bent shape of the molecule.

Hydrochloric acid has polar covalent chemical bond where hydrogen has oxidation umber +1  and chlorine oxidation number -1.

In molecule of methane (CH₄) all the atoms around the central element (carbon) are equivalent (four hydrogens) and it has a net dipole moment of 0 (vectors of dipole moments cancel each other, dipole moment is zero).

8 0
3 years ago
Read 2 more answers
Find the molarity and molality of 37.0 wt% Hcl. Assume the density of the acid is 1.19g/ml​
erik [133]

Answer:

a) M HCl = 32.162 mol/L

b) m HCl = 15.873 mol/Kg

Explanation:

  • wt% = (mass HCl / mass sln)×100
  • δ HCl = mass HCl / Volume sln
  • molarity = mol HCl / V sln (L)
  • molality = mol HCl / Kg solvent

∴ MW HCl = 36.46 g/mol

assuming mass sln = 1 g

∴ mass sln = 1 g = g solvent + g solute

∴ solute: HCl

⇒ 0.37 = g HCl / g sln

⇒ g HCl = 0.37 g

⇒ g ste = 1 - 0.37 = 0.63 g

⇒ Kg ste = (0.63 g)×(Kg/1000 g) = 6.3 E-4 Kg

⇒ mol HCl = (0.37 g HCl)×(mol/36.46 g HCl) = 0.010 mol HCl

∴ V sln = (0.37 g)/(1.19 g/mL) = 0.3109 mL

⇒ V sln = (0.31 mL)×( L/1000 mL) = 3.109 E-4 L

a) molarity (M):

⇒ M HCl = 0.010 mol HCl / 3.109 E-4 L

⇒ M HCl = 32.162 mol/L

b) molality (m):

⇒ m HCl = ( 0.010 mol HCl) / (6.3 E-4 Kg)

⇒ m HCl = 15.873 mol/Kg

4 0
4 years ago
Does a liquid have a shape??
Sladkaya [172]
It has the shape of the container, so yes
6 0
3 years ago
Read 2 more answers
Nuclear decay is a first-order kinetics process. What is the half-life of a radioactive isotope if it takes 233 minutes for the
-BARSIC- [3]

<u>Answer:</u> The half life of the given radioactive isotope is 43.86 minutes

<u>Explanation:</u>

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,

k = rate constant  = ?

t = time taken for decay process = 233 minutes

[A_o] = initial amount of the reactant = 0.500 M

[A] = amount left after decay process =  0.0125 M

Putting values in above equation, we get:

k=\frac{2.303}{233}\log\frac{0.500}{0.0125}\\\\k=0.0158min^{-1}

The equation used to calculate half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

where,

t_{1/2} = half-life of the reaction = ?

k = rate constant = 0.0158min^{-1}

Putting values in above equation, we get:

t_{1/2}=\frac{0.693}{0.0158min^{-1}}=43.86min

Hence, the half life of the given radioactive isotope is 43.86 minutes

8 0
3 years ago
Your lab partner accidentally trips and douses the front of your lab coat and shirt with a hazardous material. The TA immediatel
Alja [10]

Answer:

Remove your shirt and any other clothing that were in contact with the chemical

Explanation:

A hazardous chemical has the capacity to cause damage to the body when it comes in contact with the skin. Many hazardous chemicals are capable of being absorbed into the body via the skin.

Once your lab coat is already doused with the chemical and it has started soaking into you clothing, you must remove your lab coat, shirt and all clothing that were in contact with the hazardous chemical as a safety measure to avoid absorption of the chemical into the body via the skin. Some of these chemicals also cause damages directly to the skin and this must be avoided.

8 0
3 years ago
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