Question

Approximately how many moles of chlorine make up 1.79 x 10^23 atoms of chlorine?

Answer 1

Answer

The answer of given question is 0.13 mol

Explanation

1 mol of chlorine (Cl) contain =$6.022^{23} N_{A} atoms$ atoms (Avogadro Number)

So, we have to determine how many moles of Cl will be contain for $0.79 * 10^{23} N_{A}$atoms.

As we know unit method

$6.022^{23} N_{A} = 1 mol of chlorine (Cl)$

$1 N_{A} atom = 1/6.022^{23} N_{A}$}

$0.79 * 10 ^{23} N_{A} = 1 mol * 0.79^{23} N_{A}/6.022^{23} N_{A}$

$0.79* 10 ^{23} N_{A} = 0.13 mol$

So, the answer is 0.13 mol