Answer:
- <em>The maximum amount of copper allowed in 100 g of water is </em><u><em>0.00013 g</em></u>
Explanation:
To find the maximum amount of copper (in grams) allowed in 100 g of water use the maximum amount ratio (1.3 mg / kg) and set a proportion with the unknown amount of copper (x) and the amount of water (100 g):
First, convert 100 g of water to kg: 100 g × 1 kg / 1000 g = 0.1 kg.
Now, set the proportion:
- 1.3 mg Cu / 1 Kg H₂O = x / 0.1 kg H₂O
Solve for x:
- x = 0.1 kg H₂O × 1.3 mg Cu / 1 kg H₂O = 0.13 mg Cu
Convert mg to grams:
- 0.13 mg × 1 g / 1,000 mg = 0.00013 g
Answer: 0.00013 g of copper.
Answer:
idvd has a very high performance and a lot more than just the right side to get it all out
Answer: its the first one buster
<span>Not to be confused with tetration.
This article is about volumetric titration. For other uses, see Titration (disambiguation).
Acid–base titration is a quantitative analysis of concentration of an unknown acid or base solution.
Titration, also known as titrimetry,[1] is a common laboratory method of quantitative chemical analysis that is used to determine the unknown concentration of an identified analyte. Since volume measurements play a key role in titration, it is also known as volumetric analysis. A reagent, called the titrant or titrator[2] is prepared as a standard solution. A known concentration and volume of titrant reacts with a solution of analyte or titrand[3] to determine concentration. The volume of titrant reacted is called titration volume</span>
Answer:
Volume = 45.62L
Explanation:
Data;
V1 = 54.9L
T1 = 64°C = (64 + 273.15)k = 337.15K
T2 = 7°C = (7 + 273.15)k = 280.15K
V2 = ?
From Charles law,
The volume of a fixed mass of gas is directly proportional to its temperature provided that pressure remains constant
V = KT, K = V / T = V1 / T1 = V2 / T2 = V3 / T3 =.........= Vn / Tn
(54.9 / 337.15) = (V2 / 280.15)
V2 = (54.9 * 280.15) / 337.15
V2 = 45.618L
V2 = 45.62L
