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3 years ago

Which are points drawn in this figure?

Mathematics

2 answers:

professor190 [17]3 years ago

6 0

S, r, c and m

hope this helps :)

serg [7]3 years ago

5 0

A and B. S and R.
From the pic those seem correct

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Jaina and Tomas compare their compound interest accounts to see how much they will have in the accounts after three years. They

stellarik [79]

Formula for compound interest is

Interest = Amount - Principal

Interest = $P(1+r)^{t}$ - P

Where r = rate in percent

t = time in years

For Jaina,

P = $300

r= 7%

t = 3 yrs

So, Interest = $300(1+0.07)^{3}$ - 300

For Tomas

P = $400

r= 4%

t = 3 yrs

So, Interest = $400(1+0.04)^{3}$ - 400

So pair of equations for Jaina and Tomas are

Interest = $300(1+0.07)^{3}$ - 300

Interest = $400(1+0.04)^{3}$ - 400

5 0

3 years ago

Read 2 more answers

The half-life is a substance is 375 years. If 70 grams is present now, how much will be present in 500 years?

Lynna [10]

Answer:

27.76 grams will be present in 500 years

Step-by-step explanation:

The given formula is $A=A_{o}e^{kt}$ , where A is the value of the substance in t years, and $A_{o}$ is the initial value

∵ The half-life is a substance is 375 years

- Substitute A by $\frac{1}{2}A_{o}$ and t by 375 to find the value of k

∴ $\frac{1}{2}A_{o}=A_{o}e^{375k}$

- Divide both sides by $A_{o}$

∴ $\frac{1}{2}=e^{375k}$

- Insert ㏑ in both sides

∴ ㏑( $\frac{1}{2}$ ) = ㏑ ( $e^{375k}$ )

- Remember ㏑ ( $e^{n}$ ) = n

∵ ㏑ ( $e^{375k}$ ) = 375 k

∴ ㏑( $\frac{1}{2}$ ) = 375 k

- Divide both sides by 375

∴ k ≈ -0.00185

∴ $A=A_{o}e^{-0.00185t}$

∵ 70 grams is present now

- That means the initial value is 70 grams

∴ $A_{o}$ = 70

∵ The time is 500 years

∴ t = 500

- Substitute the values of $A_{o}$ and t in the formula

∵ $A=70e^{-0.00185(500)}$

∴ A = 27.76

∴ 27.76 grams will be present in 500 years

3 0

3 years ago

Fifteen over eight plus two over five plus negative seven over eight

Luden [163]

5589d7du6a5s5s55did7duei

4 0

3 years ago

A bag contains 2 white balls 4 green balls. 2 balls are drawn from the bag without replacement. use a tree diagram to find the p

Vitek1552 [10]

Answer: 1 in 3rd chance

Step-by-step explanation:

The are 6 balls and 4 are green and the other 2 are white so if you but it in fraction form it would be 2 over 6 with simply to 1 over 3

3 0

3 years ago

The tallest living man at one time had a height of 230 cm. The shortest living man at that time had a height of 91.3 cm. Heights

kap26 [50]

Answer: The shortest living man at that time had the height that was more extreme.

Step-by-step explanation:

We will z scores to solve this exercise. The formula we need is:

$z=\frac{x-\mu}{\sigma}$

Where $x$ is the raw score, $\mu$ is the mean and $\sigma$ is the standard deviation.

We know at that time heights of men had a mean of 170.53 centimeters and a standard deviation of 5.91 centimeters, then:

$\u=170.53\\\\\sigma=5.91$

Knowing that the tallest living man at that time had a height of 230 centimeters, we get:

$z=\frac{230-170.53}{5.91}\approx10.07$

And knowing that the shortest living man at that time had a height of 91.3 centimeters, we get:

$z=\frac{91.3-170.53}{5.91}\approx-13.40$

Based on this, we can conclude that the shortest living man at that time had the height that was more extreme.

3 0

3 years ago