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Ksivusya [100]
3 years ago
6

1. Using a typical frequency value for the initiating event and PFD values provided in class lectures, estimate the mishap or co

nsequence frequency for a cooling water failure if the system to be cooled is provided with the following IPLs: (1) Personnel action with a 10 min response time, and (2) A basic process control system (BPCS).
Engineering
1 answer:
algol133 years ago
5 0

Answer:

a basic process control system is necessary as long as the work by the personnel in charge is efficient, this reduces by 90% the errors or failures to calculate the system to operate

Explanation:

Production staff human error

 Another reason why a breakdown can occur is due to an error of the production personnel. This error, in turn, can originate from:

Error of interpretation of an indicator during the normal operation of the equipment, which causes the operator or driver of the installation to make the wrong decision

Incorrect performance in the event of a machine failure. For example, introducing water into a hot boiler in which water has been lost visually; as it is not known how much water is inside, it may be empty and hot, so when water is introduced it will produce instant vaporization, with the consequent increase in pressure that can even cause the boiler to explode.

Physical factors of the operator: this may not be in perfect condition to carry out his work, due to dizziness, sleep, fatigue accumulated by long working hours, illness, etc.

Psychological factors, such as demotivation, problems external to work, etc., greatly influence the proliferation of operational errors

Lack of clear systematic instructions, such as procedures, technical instructions, etc., or poor implementation of these  Lack of training

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Select all that apply: Contaminated sharps should<br><br> not be<br><br> ----
PIT_PIT [208]

Answer:

Contaminated sharps should not be bent, recapped or removed.

Explanation:

Contaminated sharps are defined as "any contaminated object that can penetrate the skin including, but not limited to, needles, scalpels, broken glass, broken capillary tubes and exposed ends of dental wires".

4 0
2 years ago
Consider a refrigerator that consumes 320 W of electric power when it is running. If the refrigerator runs only one quarterof th
ryzh [129]

Answer:

$5.184

Explanation:

The cost can be calculated using the formula: Cost = Load \ factor \times Number \ of \ hours \ \\M_{month} = M_{units} \times W\\

Before using this, we require the following conversions:

<em>320 W → kW:</em>

\frac {320}{1000} = 0.32

<em>30 Days → Hours:</em>

30 \times 24 = 720

Using the above stated formula:

M_{month} = 0.09 \times 0.32 \times \frac{1}{4} \times 720 = 5.184

4 0
2 years ago
What relationship is there between the hydraulic system and power, force, energy, resources, and types of energy?
pshichka [43]

Answer:

Well to me there all energy resources.

Explanation:

7 0
3 years ago
Read 2 more answers
A girl operates a radio-controlled model car in a vacant parking lot. The girl's position is at the origin of the xy coordinate
lawyer [7]

Answer:

a) 17.20

b) 11.31

c) 14.42

d) 12.65

Explanation:

(a)

The girl is at the origin of the x,y coordinates  (i.e 0,0,0  )

the position vector of the car at time 't' secs is

\vec{r}= 2+2t^2, 6+t^3,0

at t=2s,  the position vector is

\vec{r}= 10, 14,0

Therefore, the the distance between the car and the girl is

s= \sqrt{(10-0)^2+(14-0)^2+(0-0)^2)}\

s = 17.20

(b)

The position of the car at  t = 0s is \vec{r}_0 = 2,6,0

The position of the car at t = 2s is \vec{r}_2 = 10,14,0

The distance of the car traveled in the interval from t=0s to t=2 s is as follows:

s_{02}= \sqrt{(10-2)^2+(14-6)^2+(0-0)^2)} \\ \\ s_{02}  = 11.31

(c)

The position vector of the car at time 't' secs is

\vec{r}= 2+2t^2, 6+t^3,0

The velocity of the car is

\vec{v}=\dfrac{d\vec{r}}{dt}= 4t, 3t^2,0

the direction of the car's velocity at t = 2s is  going to be

\vec{v}\mid _t=2 8, 12,0

Thus; The speed of the car is

v_{t=2}= \sqrt{8^2+12^2+0^2} \\ \\  v_{t=2}= 14.42

(d)    the car's acceleration is:

\vec{a}=\frac{d\vec{v}}{dt}= 4, 6t,0

The magnitude of car's acceleration at t=2s is

\mid \vec{a}\mid _{t=2}=\sqrt{4^2+12^2+0^2} \\ \\ \mid \vec{a}\mid _{t=2}= 12.65

5 0
3 years ago
A car moves along a circular track of radius 250 ft such that its seed for a short period of time 0&lt;_ t &lt;_ 4s, is v = 3(t
beks73 [17]

Answer: a) -5 ft/s²

B) 4.5 ft

Explanation: Radius= 250ft

Velocity V = 3(t-t²)ft/s

A). When t= 3 s, the acceleration is

dv/dt = 1-2t

dv/dt = 1- 2(3)

= 1-6

= -5 ft/s²

B. How far it traveled in 3 sec

Distance= 3t²/2 -t³/3 ft

Substituting 3

Distance = 27/2 - 9

= 13.5 - 9

= 4.5 ft

7 0
3 years ago
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