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SSSSS [86.1K]
3 years ago
13

What is the velocity of a wave that has a frequency of 2 Hertz and a wavelength of 2 meters?

Physics
1 answer:
scZoUnD [109]3 years ago
7 0

-- <em>What is the velocity of a wave that has a frequency of 2 Hertz and a wavelength of 2 meters? </em>

Wavespeed = (frequency) x (wavelength)

Wavespeed = (2/second) x (2 meters)

<em>Wavespeed = 4 meters/second</em>

<em>-- What is the frequency of a 5 meter wave that has a velocity of 1 m/s?</em>

Frequency = (Wavespeed) / (wavelength)

Frequency = (1 m/s) / (5 m)

<em>Frequency = 1/5 Hz  (0.2 Hz)</em>

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If you attach a 100 g mass to the spring whose data are shown in the graph, what will be the period of its oscillations?
ycow [4]

if for a force of 0.5 N we have a displacement of -0.02m we can calculate the elastic constant(k) with the formula F=-kx(F=0.5N x=-0.02)

k=F/x k=0.5/0.02=25N/m

now we can calculate the period by the formula

T=2π√(m/k)

in the mass we convert grams to kilograms so 100g=0.1kg

T=6.28√(0.1/25)⇒T=0.39seconds

8 0
3 years ago
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Pedro uses a bar magnet to pick up a nail. He then
lisabon 2012 [21]

The nail has become a temporary magnet, while the

bar magnet remains a permanent magnet.

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3 years ago
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2.19 The drag characteristics of a blimp traveling at 4 m/s are to be studied by experiments in a water tunnel. The prototype is
Naily [24]

Answer:

Vm=0.894m/s

Explanation:

From the question we are told that

Velocity if travel v=4m/s

Diameter of  prototype d_1=20m and d_2=110m

Scale ratio=\frac{1}{20}

Generally Velocity of of the model using Froud's model is mathematically given as

Fm=Fp

\frac{Vm}{\sqrt{Lmg}} =\frac{Vp}{\sqrt{Lpg}}

Vm=Vp*\frac{Vp}{\sqrt{Lpg} }

Vm=4*\frac{1}{\sqrt{20}}

Vm=0.894m/s

8 0
3 years ago
Professor Stefanovic is spinning a bucket of water by extending his arm and rotating his shoulder in class to show the effects o
anyanavicka [17]

Answer:

a ) 2.368 rad/s

b) 3.617 rad/s

Explanation:

the minimum angular velocity that Prof. Stefanovic needs to spin the bucket for the water not to fall out can be determined by applying force equation in a circular path

i.e

F_{inward } = F_G + F_T   ------ equation (1)

where;

F_{inward} = m *a_c

F_{inward} = m*r* \omega^2

Also

F_G = m*g

F_T = 0          since; that is the initial minimum angular velocity to keep the water in the bucket

Now; we can rewrite our equation as :

mr \omega^2= mg + 0\\\omega^2 = \frac{m*g}{m*r}\\\omega^2 = \frac{g}{r}\\\omega = \sqrt{\frac{g}{r} \ \  }     ------ equation \ \ \ {2}

So; Given that:

The rope that is attached to the bucket is lm long  and his arm is 75 cm long.

we have our radius r = 1 m +  75 cm

= ( 1 + 0.75 ) m

= 1.75 m

g = acceleration due to gravity = 9.81 m/s²

Replacing our values into equation (2) ; we have:

\omega = \sqrt{ \frac{9.81}{1.75}}\\\omega = 2.368 \  rad/s

b) if he detaches the rope and spins the bucket by holding it with his hand ; then the radius = 0.75 m

∴

\omega = \sqrt{ \frac{9.81}{0.75}}\\\omega = 3.617 \  rad/s

4 0
4 years ago
Assume this car is driven off a cliff. How many arrows of force need to be drawn in the free body diagram? Assum no air resistan
kirza4 [7]

Answer:

4

Explanation:

friction

weight

normal reaction

force to overcome inertia

4 0
3 years ago
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