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alukav5142 [94]

3 years ago

13

2.19 The drag characteristics of a blimp traveling at 4 m/s are to be studied by experiments in a water tunnel. The prototype is

20 m in diameter and 110 m long. The model is one-twentieth scale. What velocity must the model have for dynamic similarity

1 answer:

Naily [24]3 years ago

8 0

Answer:

$Vm=0.894m/s$

Explanation:

From the question we are told that

Velocity if travel $v=4m/s$

Diameter of prototype $d_1=20m$ and $d_2=110m$

Scale ratio= $\frac{1}{20}$

Generally Velocity of of the model using Froud's model is mathematically given as

$Fm=Fp$

$\frac{Vm}{\sqrt{Lmg}} =\frac{Vp}{\sqrt{Lpg}}$

$Vm=Vp*\frac{Vp}{\sqrt{Lpg} }$

$Vm=4*\frac{1}{\sqrt{20}}$

$Vm=0.894m/s$

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A charge q of 1.3 × 10-16 coulombs moves from point A to a lower potential at point B in an electric field of 3.2 × 102 newtons/

LUCKY_DIMON [66]

Explanation :

It is given that,

Charge, $q=1.3\times 10^{-16}\ C$

Electric field, $E=3.2\times 10^2\ N/C$

Distance, $d=1.1\times 10^{-2}\ m$

The work done is stored in the form of potential energy.

$W=F.d$

$\because F=qE$

So, $W=qE\ d$

$W=1.3\times 10^{-16}\ C\times 3.2\times 10^2\ N/C\times 1.1\times 10^{-2}\ m$

$W=4.576\times 10^{-16}\ J$

Hence, this is the required solution.

5 0

3 years ago

Read 2 more answers

A wheel, starting from rest, rotates with a constant angular acceleration of 1.80 rad/s^2. During a certain 7.00 s interval, it

lora16 [44]

Answer:

a) 1.3 rad/s

b) 0.722 s

Explanation:

Given

Initial velocity, ω = 0 rad/s

Angular acceleration of the wheel, α = 1.8 rad/s²

using equations of angular motion, we have

θ2 - θ1 = ω(0)[t2 - t1] + 1/2α(t2 - t1)²

where

θ2 - θ1 = 53.2 rad

t2 - t1 = 7s

substituting these in the equation, we have

θ2 - θ1 = ω(0)[t2 - t1] + 1/2α(t2 - t1)²

53.2 =ω(0) * 7 + 1/2 * 1.8 * 7²

53.2 = 7.ω(0) + 1/2 * 1.8 * 49

53.2 = 7.ω(0) + 44.1

7.ω(0) = 53.2 - 44.1

ω(0) = 9.1 / 7

ω(0) = 1.3 rad/s

Using another of the equations of angular motion, we have

ω(0) = ω(i) + α*t1

1.3 = 0 + 1.8 * t1

1.3 = 1.8 * t1

t1 = 1.3/1.8

t1 = 0.722 s

5 0

3 years ago

How much time does it take for a car to accelerate from 3.44 m/s to 20.9 m/s if the average acceleration is 6.00 m/s^3

miv72 [106K]

Do you go to GA Connexus Academy??

4 0

4 years ago

Read 2 more answers

Transcranial magnetic stimulation (TMS) is a noninvasive technique used to stimulate regions of the human brain. A small coil is

Xelga [282]

Answer:

$7.3114*10^{-5}V$

Explanation:

To give a solution to the exercise, it is necessary to consider the concepts related to magnetic flux and Faraday's law of induction. Faraday's law states that the voltage induced in a closed circuit is directly proportional to the speed with which the magnetic flux that crosses any surface with the circuit as an edge changes over time.

It is represented under the equation,

$\epsilon = N \frac{\Delta\Phi}{\Delta t}$

Where,

$\epsilon$ is the induced electromotive force

N = Number of loops

$\Delta t$ = Time

$\Delta\Phi$ = Magnetic Flux

For definition the change in magnetic flux is:

$\Delta \Phi = \Delta B A cos\phi$

Where,

B= Magnetic field

Substituting at the first equation we have

$\epsilon = N \frac{\Delta B A Cos\phi}{\Delta t}$

$\epsilon = N \frac{(B_2-B_1) (\pi r^2) Cos\phi}{\Delta t}$

Our values are given by,

N = 1 turn

$B_2 = 1T$

$B_1 = 0T$

r = 1.6mm

$\phi = 0\°$

$\Delta t = 100ms$

Replacing,

$\epsilon = (1) \frac{(1-0) (\pi (1.6*10^{-3})^2) Cos(0)}{110*10^{-3}}$

$\epsilon = 7.311*10^{-5}V$

<em>Therefore the magnitud of the induced emf around a horizontal circle of tissue is $7.3114*10^{-5}V$ </em>

8 0

4 years ago

A car is traveling at 96km/hr. what is the acceleration of a car traveling a distance of 100m and come to rest?

8090 [49]

Answer:

Explanation:

v² = u² + 2as

v = 0

u = 96 / 3.6 = 26.7 m/s

0² = 26.7² + 2a100

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the negative sign indicated the acceleration vector opposes the (assumed positive) initial velocity vector direction.

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3 years ago