Answer:
The change in momentum of the car is 16380.8 kg.m/s
Explanation:
Given;
mass of the car, m = 1600 kg
time of motion, t = 4.20s
force of friction on the car, F = 3900 N
final velocity of the car after the brakes were applied, v = 0
The initial velocity of the car during the motion is calculated as;
The change in momentum of the car is calculated as;
ΔP = mu
ΔP = 1600 x 10.238
ΔP = 16380.8 kg.m/s
Answer:
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Explanation:
Explanation:
volume=3x4x6=72cm³
density=mass/volume
so:
184.32/72=<u>2</u><u>.</u><u>5</u><u>6</u><u>g</u><u>/</u><u>cm³</u><u> </u><u>for</u><u> </u><u>the</u><u> </u><u>block</u>
Answer:
Your friend is 2.143 blocks from the restaurant.
You are 2.857 blocks from the restaurant.
Explanation:
Let t be the time both you and your friend take to walk to the restaurant.
The distance (m) from your building to the restaurant is your walking time t times your speed v1
Similarly the distance (m) from your friend building to the restaurant:
Let b be the length (in m) of a block, the total distance of 5 blocks is 5b
So your friend are 2.143b meters from the restaurant, since each block is b meters long, 2.143b meters would equals to 2.143b/b = 2.143 blocks. And you are 5 - 2.143 = 2.857 blocks from the restaurant.