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elixir [45]
3 years ago
5

A forest fire makes a loud roaring sound. The explosive processes that release energy from the Sun occur at a much higher temper

ature. Why don’t you hear a roaring sound from the sun?
Physics
2 answers:
snow_tiger [21]3 years ago
8 0
Sound needs a material medium to propagate through. There is no medium in space, so sound from the sun can't GO anywhere.
The other interesting question is how heat and light from the sun DO get here.
KengaRu [80]3 years ago
5 0
Becuase for sound to happen you need air, And there is no oxygen is space. 

You might be interested in
This position-time graph describes an object's motion. Use it to determine the
kirza4 [7]

We're happy that you're asking for the "displacement", because displacement is simply the straight-line distance between the start-point and end-point, and we don't care about any of the motions or gyrations along the way.

From the graph:

-- The location of the object at time-zero, when time begins, is  10 meters.

-- The location of the object after 6.0 seconds is  4 meters.

-- The distance between the start-point and end-point is

(final location) - (initial location)

-- So Displacement = (4 meters) - (10 meters)

<em>Displacement = -6 meters</em>

3 0
3 years ago
Is a process that modifies light waves so they vibrate in a single plane
madam [21]

The process you're fishing for is "polarization", but that's a

misleading description.

Polarization doesn't do anything to change the light waves. 

It simply filters out (absorbs, as with a polarizing filter) the

light waves that aren't vibrating in the desired plane, and

allows only those that are to pass.

The intensity of a light beam is always reduced after

polarizing it, because much (most) of the original light

has been removed.

A laser light source may be thought of as an exception,

since everything coming out of the laser is polarized.

8 0
4 years ago
HELP ME PLZ
Nadusha1986 [10]

Answer: 1200 000 J = 1.2 MJ

Explanation: Ek = 0.5 mv² = 0.5 · 1500 kg· (40 m/s)²

3 0
3 years ago
Hi please answer and show your work​
jek_recluse [69]

Answer:

\huge\boxed{\sf P.E. = 240\ MJ}

\huge\boxed{\sf K.E. = 19.6\ MJ}

Explanation:

<u>Given:</u>

Mass = m = 200,000 kg

Vertical Distance = h = 120 m

Speed = v = 14 m/s

Acceleration due to gravity = g = 10 m/s²

<u>Required:</u>

1) Gravitational Potential Energy = P.E = ?

2) Kinetic Energy = K.E. = ?

<u>Formula:</u>

1) P.E. = mgh

2) K.E. = \displaystyle \frac{1}{2} mv^2

<u>Solution:</u>

1) P.E. = (200,000)(10)(120)

P.E. = 240,000,000 Joules

P.E. = 240 Mega Joules

P.E. = 240 MJ

2) K.E. = 1/2 (200000)(14)^2

K.E. = (100000)(196)

K.E. = 19,600,000 Joules

K.E. = 19.6 MJ

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
4 0
3 years ago
You are given three resistors with the following resistances: R1 = 6.32 Ω, R2 = 8.13 Ω, and R3 = 2.29 Ω. What is the largest equ
andreyandreev [35.5K]

Answer:

The largest equivalent resistance yu can build using these three resistors is a Serie Resistance with the value of R= 16.74 Ω

Explanation:

Adding Resistances in serie is the way to build de largest equivalent value possible.

Rt= R1+R2+R3

Rt= 6.32 + 8.13 + 2.29

Rt= 16.74Ω

5 0
3 years ago
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