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3 years ago

Pedro uses a bar magnet to pick up a nail. He then

Physics

2 answers:

lisabon 2012 [21]3 years ago

7 0

The nail has become a temporary magnet, while the

bar magnet remains a permanent magnet.

MA_775_DIABLO [31]3 years ago

3 0

Answer:

Explanation:

bababooey

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Erase all the trajectories, and fire the pumpkin vertically again with an initial speed of 14 m/s. As you found earlier, the max

yanalaym [24]

Answer:

$\theta=39.49^{\circ}$

Explanation:

Maximum height of the pumpkin, $H_{max}=9.99\ m$

Initial speed, v = 22 m/s

We need to find the angle with which the pumpkin is fired. the maximum height of the projectile is given by :

$H_{max}=\dfrac{v^2\ sin^2\theta}{2g}$

On rearranging the above equation, to find the angle as :

$\theta=sin^{-1}(\dfrac{\sqrt{2gH_{max}}}{v})$

$\theta=sin^{-1}(\dfrac{\sqrt{2\times 9.8\times 9.99}}{22})$

$\theta=39.49^{\circ}$

So, the angle with which the pumpkin is fired is 39.49 degrees. Hence, this is the required solution.

8 0

3 years ago

Richard is driving home to visit his parents. 135{\rm mi} of the trip are on the interstate highway where the speed limit is 65{

nydimaria [60]

Answer:

time spent = 0.2276

Explanation:

given data

distance = 135 mi

usual speed = 65 mph

today speed = 73 mph

solution

we get here time that is express as

time = $\frac{distance}{speed}$ ...................1

usual time = $\frac{135}{65}$ = 2.0769 h

today time = $\frac{135}{73}$ = 1.8493 h

so we get here time spent as

time spent = 2.0769 h - 1.8493 h

time spent = 0.2276

6 0

4 years ago

What is the momentum of a 750kg car traculing at a velocity of 24m/s

m_a_m_a [10]

The answer is 18000 kgm/s

Momentum is mass times velocity so just do 750•24.

7 0

3 years ago

The average lifetime of μ-mesons with a speed of 0.95c is measured to be 6 x 10^6 s. Find the average lifetime of μ-mesons in a

Mnenie [13.5K]

Answer:

19.2*10^6 s

Explanation:

The equation for time dilation is:

$t = \frac{t'}{\sqrt{1-\frac{v^2}{c^2}}}$

Then, if it is observed to have a life of 6*10^6 s, and it travels at 0.95 c:

$t = \frac{6*10^6}{\sqrt{1-\frac{(0.95c)^2}{c^2}}} = 19.2*10^6 s$

It has a lifetime of 19.2*10^6 s when observed from a frame of reference in which the particle is at rest.

7 0

4 years ago

A charge of 5.67 x 10^-18 C is placed 3.5 x 10^-6 m away from another charge of -

Fudgin [204]

+ 1.58 e -15

Please hit thanks button! :)

5 0

2 years ago