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elena-14-01-66 [18.8K]
3 years ago
14

Pedro uses a bar magnet to pick up a nail. He then

Physics
2 answers:
lisabon 2012 [21]3 years ago
7 0

The nail has become a temporary magnet, while the

bar magnet remains a permanent magnet.

MA_775_DIABLO [31]3 years ago
3 0

Answer:

B

Explanation:

bababooey

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Answer it fast and no spamming....! !
ExtremeBDS [4]

Answer:

When the resistances are connected in the parallel the equivalent resistance will be always less than the value of the lowest resistance in the parallel circuit.

The equivalent resistance in the parallel circuit can be calculated using the following formula.

1/R=1/R1+1/R2+1/R3

1/R= 1/10+1/20+1/30

1/R=(6+3+2)/60

1/R=11/60

R=60/11

R=5.45 Ohms

3 0
3 years ago
Blood is accelerated from rest to 30.0 cm/s in a distance of 1.80 cm by the left ventricle of the heart. (a) Make a sketch of th
Mila [183]

Answer:

a. Picture attached

b. V, X

c. t=0.12 s

d. It makes sense cosidering that a normal heart beat rate is between 60 and 100 beats per minute (bpm).

Explanation:

First we have to identify the unknown of this problem:

a: acceleration\\t: time

Considering the characteristics of the problem and that distance and velocity are specified, the acceleration is constant, for that reason we use the equations of uniformly accelerated motion as follows:

v=v_{0}+at\\ x=x_{0}+ v_{0}+\frac{1}{2}at^{2}

If we reorganize the equations, considering that x_{0} and v_{0} are zero because motion starts from rest , we have:

a=\frac{v}{t} \\x=\frac{1}{2}at^{2}  =\frac{1}{2}\frac{v}{t} t^{2}=\frac{1}{2} vt\\t=\frac{2x}{v} \\t=\frac{2*1.80cm}{30.0\frac{cm}{s} } \\t=0.12 s

Finally, the analysis of the result leaves us to understand why the normal heart beat rate varies between 60 and 100 bpm.

6 0
3 years ago
A 1 m3tank containing air at 10oC and 350 kPa is connected through a valve to another tank containing 3 kg of air at 35oC and 15
Sveta_85 [38]

Answer:

- the volume of the second tank is 1.77 m³

- the final equilibrium pressure of air is 221.88 kPa ≈ 222 kPa

Explanation:

Given that;

V_{A} = 1 m³

T_{A} = 10°C = 283 K

P_{A} = 350 kPa

m_{B} = 3 kg

T_{B} = 35°C = 308 K

P_{B} = 150 kPa

Now, lets apply the ideal gas equation;

P_{B} V_{B} = m_{B}RT_{B}

V_{B} = m_{B}RT_{B} / P_{B}

The gas constant of air R = 0.287 kPa⋅m³/kg⋅K

we substitute

V_{B} = ( 3 × 0.287 × 308) / 150

V_{B} = 265.188 / 150  

V_{B} = 1.77 m³

Therefore, the volume of the second tank is 1.77 m³

Also, m_{A} =  P_{A}V_{A} / RT_{A} = (350 × 1)/(0.287 × 283) = 350 / 81.221

m_{A}  = 4.309 kg

Total mass, m_{f} = m_{A} + m_{B} = 4.309 + 3 = 7.309 kg

Total volume V_{f} = V_{A} + V_{B}  = 1 + 1.77 = 2.77 m³

Now, from ideal gas equation;

P_{f} =  m_{f}RT_{f} / V_{f}

given that; final temperature T_{f} = 20°C = 293 K

we substitute

P_{f} =  ( 7.309 × 0.287 × 293)  / 2.77

P_{f} =  614.6211119 / 2.77

P_{f} =  221.88 kPa ≈ 222 kPa

Therefore, the final equilibrium pressure of air is 221.88 kPa ≈ 222 kPa

6 0
3 years ago
An electric field of 1.27 kV/m and a magnetic field of 0.490 T act on a moving electron to produce no net force. If the fields a
lesantik [10]

Answer:

v = 2591.83 m/s

Explanation:

Given that,

The electric field is 1.27 kV/m and the magnetic field is 0.49 T. We need to find the electron's speed if the fields are perpendicular to each other. The magnetic force is balanced by the electric force such that,

qE=qvB\\\\v=\dfrac{E}{B}\\\\v=\dfrac{1.27\times 10^3}{0.49}\\\\v=2591.83\ m/s

So, the speed of the electron is 2591.83 m/s.

8 0
3 years ago
Please help!
o-na [289]
The formula PE(Potential Energy)= mgh

4 0
3 years ago
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