Question

2Al + 6HCl ? 2AlCl3 + 3H2 If the chemical reaction produces 129 grams of AlCl3, how many grams of H2 are also produced?

Answer 1

Answer:B 2.92

Explanation: its correct my guy

Answer 2

Answer:

2.83848 grams of $H_{2}$ are produced

Explanation:

Assuming that the reaccions continues until the total consumption of the reagents, it is possible to establish:

1 mol Al = 1 mol $AlCl_{3}$

2 mol $AlCl_{3}$ = 3 mol $H_{2}$

Then, by looking at the periodic table, it is possible to know the molar wheigt of the compounds:

1 mol Al = 29.9815 gr

1 mol $H_{2}$ = 2 gr

1 mol  $AlCl_{3}$ = 136.3405 gr

Reeplacing the moles with the respectly wheights of compounds:

29.9815 gr Al = 136.3405 gr $AlCl_{3}$

      X     gr Al = 129 gr $AlCl_{3}$

So, 129 grams of $AlCl_{3}$ equals to 28.3673 grams of Al.

Then, following the same line of thought:

29.963 gr Al (2 moles) = 6 gr $H_{2}$ (3 moles)

28.3673 gr Al  = Y gr $H_{2}$

So, 28.3673 grams of Al equals to 2.8384 grams of $H_{2}$.