The % mass/mass concentration of solute in the seawater sample is calculated as below
% mass = mass of the solute /mass of the solvent(sea water) x100
mass of the solute =1.295 g
mass of the solvent(sea water_) = 25.895 g
there the % mass = 1.295/25.895 x100 = 5.001 %
Derivatization means adding fluorescent labels or combining the analyte with chiral reagents or other chemicals to increase detectability.
Some analytes must be derivatized to increase their column retention or detectability.
Retention time can be referred to as the amount of time a solute spends in the stationary and mobile phases of a column.
Detectability is the ability of an analyte to get detected in the mobile phase of chromatography.
The refractometer, fluorescence detector, and UV detector are the three most popular liquid chromatography detectors. These detectors increase the detectability.
For derivatization, the fluorescence detector are used.
Learn more about derivatization
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Extensive property (like volume and mass), can be measured.
Answer:
Standard enthalpy of formation of Carbon disulfide CS2 = 87.3 KJ/mol
Explanation:
forming CS2 means that it should in the product side
C(graphite) + O2 → CO2 ΔH = -393.5
2S(rhombic) + 2O2 → 2SO2 ΔH = -296.4 x 2
CO2 + 2SO2 → CS2 + 3O2 ΔH = -1073.6 x -1
the second reaction is multiplied by 2 so that the SO2 and O2 can cancel out.
the third reaction is reversed (multiplied by -1) so that CS2 will be on the product side.
after adding the reaction and cancelling out similarities, the final reaction is: C(graphite) + 2S(rhombic) → CS2
Add ΔH to find the enthalpy of formation of CS2
ΔHf = (-393.5) + (-296.4 x 2) + (-1073.6 x -1) = 87.3 KJ/mol
be aware of signs
Answer:
24 g of C are needed to produce 1mol of CH₄
Explanation:
The reaction is:
2C (s) + 2H2O (l) → CH4(g) + CO2 (g)
2 moles of carbon react with 2 moles of water in order to produce 1 mol of methane and 1 mol of carbon dioxide.
If we want to produce 1 mol of methane, we need 2 moles of C
Let's find out the mass → 2 mol . 12 g/1 mol = 24g