Question

The compound adrenaline contains 56.7 % c, 6.56 % h, 28.37% o and 8.28 % n by mass. what is the empirical formula for adrenaline?

Answer 1

Answer:- An empirical formula of adrenaline is $C_8H_1_1O_3N$ .

Solution:- Convert given percentages to moles and then calculate the mol ratio to get the simplest whole number ratio of moles of atoms which is the empirical formula of the compound.

$C=\frac{56.7}{12}$ = 4.725 mol

$H=\frac{6.56}{1}$ = 6.56 mol

$O=\frac{28.37}{16}$ = 1.773 mol

$N=\frac{8.28}{14}$ = 0.591 mol

let's calculate the mol ratio now. To calculate the mole ratio, we divide the moles of each by moleso f N as it's the least one:

$C=\frac{4.725}{0.591}$ = 8

$H=\frac{6.56}{0.591}$ = 11

$O=\frac{1.773}{0.591}$ = 3

$N=\frac{0.591}{0.591}$ = 1

So, an empirical formula of adrenaline is $C_8H_1_1O_3N$ .