The laboratory procedure that best illustrate the law of conservation is
heating 100 g of CaCo3 to produce 56 g of CaO (answer C)
<u><em>explanation</em></u>
According to the law of mass conservation , the mass of the reactant must be equal to the mass of the product.
According to option c Heating 100 g CaCO3 to produces 56 g CaO ( 40 +16=56)
The remaining mass = 100-56 = 44 which would the mass of CO2 [ 12 + (16 x2)]= 44 since CaCO3 decomposes to produce CaO and CO2
Therefore the mass of reactant= 100g
mass of product = 56 g +44 g =100
Therefore the laboratory procedure for decomposition of CaCO<em>3</em> illustrate the law of mass conservation since the mass of reactant = mass of product.
I believe that there are 12 oxygen atoms in aluminum sulfate, And 1 Sulfur and 2 aluminum. If you need anything else let me know.
Answer:
2
Explanation:
Each orbital can hold two electrons. One spin-up and one spin-down.
Answer:
c. 0.1 M Ga₂(SO₄)₃
Explanation:
The boiling point increasing of a solvent due the addition of a solute follows the formula:
ΔT = K*m*i
<em>Where K is boiling point increasing constant (Depends of the solute), m is molality = molarity when solvent is water, and i is Van't Hoff factor.</em>
<em />
That means the option with the higher m*i will be the solution with the highest boiling point:
a. NaCl has i = 2 (NaCl dissociates in Na⁺ and Cl⁻ ions).
m* i = 0.20*2 = 0.4
b. CaCl₂; i = 3. 3 ions.
m*i= 0.10M * 3 = 0.3
c. Ga₂(SO₄)₃ dissolves in 5 ions. i = 5
m*i = 0.10M*55 = 0.5
d. C₆H₁₂O₆ has i = 1:
m*i = 0.2M*1 = 0.2
The solution with highest boiling point is:
<h3>
c. 0.1 M Ga₂(SO₄)₃</h3>
