Given parameters:
Initial volume = 120ml
Initial temperature = 35°C
Initial pressure = 1.2bar
Final volume = 180ml
Final temperature = 35°C
Unknown:
Final pressure = ?
To solve this problem, we apply the combined gas law. The expression is given below;
Where P₁ is the initial pressure
P₂ is the final pressure
V₁ is the initial volume
V₂ is the final volume
T₁ is the initial temperature
T₂ is the final temperature
We need to convert the parameters to standard units
take the volume to dm³;
1000ml = 1dm³
120ml = 
dm³ = 0.12dm³ = initial volume
Final volume;
1000ml = 1dm³
180ml = 
dm³ = 0.18dm³
Now, the temperature;
K = 273 + °C
Initial temperature = 273 + 35 = 308k
Final temperature = 308k
We then input the parameters into the equation;
Solving for P₂;
P₂ = 0.8bar
The new pressure or final pressure in the vessel is 0.8bar
Answer:
Collagen is a "fibrous proteins" present in the extracellular matrix.
Explanation:
Protein are made up of hundreds or thousands of smaller units called amino acids and is made of carbon, hydrogen, oxygen, nitrogen and sometimes sulfur and is found in many foods. Proteins are organic molecules found in living organisms.
There are three types of proteins; fibrous, globular, and membrane.
Collagen which is a fibrous proteins, form muscle fiber, tendons, connective tissue and bone.
Collagen are naturally occurring proteins that consist of single molecules made up of amino-acids, which are in turn built of carbon, oxygen and hydrogen. It is mostly found in fibrous tissues such as tendons, ligaments, and skin.
The synthesis of collagen occurs in two stages: intracellular and extracellular.
Collagen is an abundant connective tissues such as cartilage, tendons, bones, and ligaments. Collagen is a contributing factor to variation in meat tenderness and texture.
Answer:
Explanation:
The formula for molality is:
There are 0.210 moles of KBr and 0.075 kilograms of pure water.
Substitute the values into the formula.
Divide.
The molality is <u>2.8 moles per kilogram</u>
Explanation:
A photon is a quantum of EM radiation. Its energy is given by E = hf and is related to the frequency f and wavelength λ of the radiation by
E=hf=hcλ(energy of a photon)E=hf=hcλ(energy of a photon),
where E is the energy of a single photon and c is the speed of light. When working with small systems, energy in eV is often useful. Note that Planck’s constant in these units is h = 4.14 × 10−15 eV · s.
Since many wavelengths are stated in nanometers (nm), it is also useful to know that hc = 1240 eV · nm.
These will make many calculations a little easier.
All EM radiation is composed of photons. Figure 1 shows various divisions of the EM spectrum plotted against wavelength, frequency, and photon energy. Previously in this book, photon characteristics were alluded to in the discussion of some of the characteristics of UV, x rays, and γ rays, the first of which start with frequencies just above violet in the visible spectrum. It was noted that these types of EM radiation have characteristics much different than visible light. We can now see that such properties arise because photon energy is larger at high frequencies.
Answer:
The reaction forming aluminum bromide is Al + 3Br2 → 2AlBr3
