Question

If 75.2 grams of Calcium Sulfate are reacted with an unlimited amount of Sodium Phosphate,

Answer 1

55.83 grams is the mass of Calcium Phosphate will be formed according to the reaction when 75.2 grams of Calcium Sulfate are reacted with an unlimited amount of Sodium Phosphate.

Explanation:

Data given:

mass of calcium sulphate reacted= 75.2 grams

atomic mass of calcium sulphate = 136.14 grams/mole

balanced chemical reaction equation:

3CaS$O_{4}$ +2 $Na_{3}$ (P$O_{4}$)$_{2}$   ⇒  $Ca_{3}$ (P$O_{4}$)$_{2}$ + 3$Na_{2}$S$O_{4}$

number of moles of calcium phosphate given will be calculated as:

number of moles = $\frac{mass}{atomic mass of 1 mole}$

        putting the values in the above formula, we get

number of moles = $\frac{75.2}{136.4}$

                             = 0.55 moles of CaS$O_{4}$ is given

From the balanced equation:

3 moles of CaS$O_{4}$ reacts to give 1 mole of calcium phosphate

so, 0.55 moles of CaS$O_{4}$ will react to form x moles of calcium phosphate

$\frac{1}{3}$ = $\frac{x}{0.55}$

3x = 0.55

x = 0.18 moles of calcium phosphate is formed

mass = number of moles x atomic mass of calcium phosphate

(atomic mass of $Ca_{3}$(P$O_{4}$)${3}$ =310.18 grams/mole)

putting the values in the formula:

mass = 0.18 x 310.18

          = 55.83 grams of calcium phosphate is formed.