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Ronch [10]
3 years ago
6

How many moles of KBr are present in 8.96 x 10^21

Chemistry
1 answer:
Gelneren [198K]3 years ago
6 0

Answer:

0.015 moles

Explanation:

  • One mole of a compound contains molecules equivalent to the Avogadro's constant, 6.022 × 10^23.
  • That is, 1 mole of a compound will have 6.022 × 10^23 molecules.

In our case, We are given 8.96 x 10^21 molecules of KBr

We need to find the number of moles in 8.96 x 10^21 molecules

1 mole of KBr = 6.022 × 10^23 molecules.

8.96 x 10^21 molecules = ?

Therefore;

(1 × 8.96 x 10^21 molecules ) ÷ 6.022 × 10^23 molecules.

 = 1.488 × 10^-2 moles

 = 0.01488 moles

= 0.015 moles

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Calculate the number of atoms in 35 g of carbon. Calculate the number of atoms in 75 g of bromine.
nata0808 [166]

Answer:

Explanation:

To calculate the number of atoms in a formula, the weight of a sample, its atomic mass from the periodic table and a constant known as Avogadro’s number are needed.

Step 1: Find the Molar Mass of the Formula

Find a periodic table of elements to find the molar mass of your sample. If your sample is made of one element, like copper, locate the atomic mass on the periodic table. Atomic mass is usually listed below the symbol for that element.

The atomic mass of carbon and bromine is 63.55 atomic mass units. This formula mass is numerically equal to the molar mass in grams/mole, and this means copper is 63.55 grams/mole.

Whether you use an individual element like copper or a molecule, the procedure for finding the atoms in a formula remains the same.

Find the molar mass of carbon and bromine on the periodic table: 63.55 grams/mole.

Understanding the Mole: The mole (often abbreviated as mol) listed above is a unit of measurement. If you sold eggs, you would talk about them in the dozens, not one by one.

A mole is a certain amount, too. If chemists want to speak about incredibly small atoms and molecules, an amount far greater than a dozen is needed. A mole is Avogadro’s number of items: 6.022 × 1023.

1 mole of C atoms = 6.022 × 1023 C atoms

1 mole of Br atoms = 6.022 × 1023 S atoms

1 mole of CBrmolecules = 6.022 × 1023 CBr molecules

1 mole of pennies = 6.022 × 1023 pennies

To give an idea of how large this number is, 1 mole of pennies would be enough money to pay all the expenses of each country on earth for about the next billion years.

Step 2: Find the Number of Moles

The example is 35 grams of C and . Change that into moles using the molar mass you found in Step 1. Chemists use ratios for this calculation.

Start with what you know and add in the molar mass ratio, so the units will cancel:

35g of C× 1 mol C/ 12 g C = 2.92mol of C

Step 3: Convert Moles to Atoms Using Avogadro’s Number

Once the amount of moles is known, the number of atoms in the formula may be calculated using Avogadro’s number. Again, use the ratio format.

Notice the number of moles is used from Step 2 to start the calculation from moles to atoms:

2.92 mol of C× 6.022 x 1023 atoms / 1 mol of C = 3.13 x 1023 molecules

To answer your example question, there are 3.13 × 1023 atoms in 32.80 grams of carbon.

Steps 2 and 3 can be combined. Set it up like the following:

32.80 g of C × 1 mol Cu / 159.17 g C × 6.022 x 1023 atoms / 1 mol of C = 3.13 x 1023 atoms in 32.80 grams of carbon

Several online sites have a number of atoms calculator. One is the Omni Calculator and is listed in the Resources section, but you’ll still need to know how to calculate molar mass (Step 1).

Historical Note: Why Is It Called Avogadro's Number?

Avogadro’s number is named after Amedeo Avogadro (1776-1856), an Italian scientist that hypothesized that equal volumes of gases at the same temperature and pressure will have the same number of particles.

Avogadro did not propose the constant, 6.022 ×1023, but because of his contributions to science, the constant was named after him. Incidentally, Avogadro first introduced his gas theory in 1811, and it was ignored for 50 years.

5 0
2 years ago
What is the empirical formula of a compound that is made of 3.80g of phosphorus and 0.371g of hydrogen?
lys-0071 [83]

You start by diving each quantity given by the atomic wight of each element:

Phosphorus (P)   \frac{3.8}{31} =0.123

Hydrogen (H)   \frac{0.371}{1} =0.371

Then you divide by the lowest number:

\frac{0.123}{0.123} = 1 for phosphorus

\frac{0.371}{0.123} = 3 for hydrogen

So the empirical formula will be:    

PH_{3}

6 0
3 years ago
Which of the following molecular compounds does NOT need the usage of prefix for the first element
Mrrafil [7]

Answer:

SO2

Explanation:

that's my answer

Sana mKatolong

3 0
2 years ago
The movement of food energy from one organism to another is called a...
vlabodo [156]
It is called a food chain
7 0
2 years ago
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How long must $542 be invested at a rate of 7% to earn $303.52 in interest
yulyashka [42]

The number of years that must be invested at  a rate of 7 % to earn$ 303.52 in interest is

    8 years

 <em><u>calculation</u></em>

  • <em><u> </u></em><em>by use of  the formula       A = P (1+  rt) </em>
  • <em>  where :  A  is the final amount  =  542 + 303.52  =$ 845.52</em>

<em>                    P  is the principal   money to be invested =  $ 542</em>

<em>                        r= rate= 7/100=0.07</em>

<em>                       t=  time required</em>

<em>=$ 845.52=$ 542( 1+  0.07 t)</em>

  • <em>open the  bracket</em>
  • <em>= $845.53= $542 + $37.94  t</em>

  • <em>like terms  together</em>

    =$  845.53 -$542  = $37.94 t

   =$303.52 =$37.94 t

  • divide both  side by  $37.94

  =  $303.52/ $   37.94  =  $37.94t/$37.94

  t=  8 years

7 0
3 years ago
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