1. 2Pb(NO₃)₂ → 2PbO + 4NO₂ + O₂
2. CH₄ + 2O₂ → CO₂ + 2H₂O
3. Cu + 2AgNO₃ → Cu(NO₃)₂ + 2Ag
4. MnO₂ + 4HCl → MnCl₂ + 2H₂O + Cl₂
5. Pb(NO₃)₂ + 2NaCl → PbCl₂ + 2NaNO₃
1)

2)
CuSO_4+Cu_2Cl_2\neq>

Answer:
Potential energy in a double bond is going to be higher than the potential energy of a single bond due to the force needed to break a double bond as opposed to a single. Single bond is weaker, which means less energy is needed to break it. Double bonds are stronger, requiring more energy to break the bond.
Explanation:
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I think is it the flask the bottle cause i had the same thing and i got it right idk maybe :)
I’m assuming in this scenario that 2.5 mols of Fe2O3 is reacting with excess reactant. Based on the balanced equation, you can see that there’s a 1:2 ratio between Fe2O3 and Fe. This means that to find the mols of Fe formed, you need to multiply the mols of Fe2O3 by 2.
2.50mol Fe2O3 * 2mol Fe/1 mol of Fe2O3 = 5.00mols Fe.