How many moles of KBr are present in 8.96 x 10^21
1 answer:
Answer:
0.015 moles
Explanation:
- One mole of a compound contains molecules equivalent to the Avogadro's constant, 6.022 × 10^23.
- That is, 1 mole of a compound will have 6.022 × 10^23 molecules.
In our case, We are given 8.96 x 10^21 molecules of KBr
We need to find the number of moles in 8.96 x 10^21 molecules
1 mole of KBr = 6.022 × 10^23 molecules.
8.96 x 10^21 molecules = ?
Therefore;
(1 × 8.96 x 10^21 molecules ) ÷ 6.022 × 10^23 molecules.
= 1.488 × 10^-2 moles
= 0.01488 moles
= 0.015 moles
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