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3 years ago

How many moles of KBr are present in 8.96 x 10^21

Chemistry

1 answer:

Gelneren [198K]3 years ago

6 0

Answer:

0.015 moles

Explanation:

One mole of a compound contains molecules equivalent to the Avogadro's constant, 6.022 × 10^23.

That is, 1 mole of a compound will have 6.022 × 10^23 molecules.

In our case, We are given 8.96 x 10^21 molecules of KBr

We need to find the number of moles in 8.96 x 10^21 molecules

1 mole of KBr = 6.022 × 10^23 molecules.

8.96 x 10^21 molecules = ?

Therefore;

(1 × 8.96 x 10^21 molecules ) ÷ 6.022 × 10^23 molecules.

= 1.488 × 10^-2 moles

= 0.01488 moles

= 0.015 moles

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Charra [1.4K]

There are several information's already given in the question. Based on the information's provided, the answer can be easily deduced.
V1 = 25 ml
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Explanation:

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The 225 g FeCl2 is about 1.8 moles.

Lyrx [107]

Answer:

$4 \frac{mol}{l}$

Explanation:

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See figure 1

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