70x0.2=5×x
X=2.8 ml
basically for these kind of questions you should use this formula: m1v1= m2v2
m is molar v is volume
Answer:
(A). H2S.
(B). BrO-.
(C). H2SbO3 .
(D). HClO4.
(E). CH3NH2.
(F). HClO > HBrO > HIO.
Explanation:
(A). The strongest acid is H2S because it has the lowest atomic size. If we move from the left side of the periodic table to the right side of the periodic table the atomic size decreases. As the atomic size decreases, it will be easier for H^+ ion to be released. Therefore, the ease of releasing Hydrogen ion makes H2S more acidic than the others in this group.
(B). BrO- is more basic because of bond pair - lone pair repulsion. BrO2- , BrO4-, and ClO2- exhibit resonance and therefore, they do not possess good basic features.
(C). H2SbO3 has the lowest pKa because the atomic size of Sb is greater than As and P , As is greater than P. This means that It is more difficult to remove Hydrogen ion from Sb.
(D). HClO4 is the Acid with the highest pKa because of high resonance.
(E). CH3NH2 is more basic because it has the highest electron Density. In BrNH2, the bromine ion reduces the electron Density.
(F). In halogens, as one goes down the group in the periodic table the acidic properties decreases, hence, HClO > HBrO > HIO.
<h3>Answer:</h3>
Ca²⁺
<h3>Explanation:</h3>
Ionization energy is defined as the minimum amount of energy required to knock out the electron from valence shell of an atom in its gaseous state. While, second Ionization energy is defined as the amount of energy required to knock out the second electron from an ion containing +1 charge in gaseous state.
Among given options Ca²⁺ is the correct choice because the calcium has lost two electrons i.e. first electron was removed by providing first ionization energy i.e.
Ca + 1st IE → Ca¹⁺ + 1 e⁻
and second electron is was removed by providing second ionization energy i.e.
Ca ¹⁺ + 2nd IE → Ca²⁺ + 1 e⁻
Answer:
8.76M
Explanation:
Given that
Mass from the density = 1141g
According to the given situation the computation of molarity of the solution is shown below:-
we will took HCL solution which is 1000mL
HCl = 28% by mass
So,
Mass of HCl in 1-litre solution is
Which gives the result of molar mass HCI is
= 319.48g
/mol
Now,
Molarity is
Which gives results of molarity is
= 8.76M