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ddd [48]
3 years ago
9

Put the following into correct SciNot: 312.5 x 10^20.1 pointYour answer​

Chemistry
1 answer:
lions [1.4K]3 years ago
7 0
Ans= 3.125*10^22

Solution:
312.5 * 10^20
=3.125 * 10^2 * 10^20
= 3.125 * 10^2+20
= 3.125 *10^22,,
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LIH2PO4 i dont know how to do this mabey you can help me figure it ou???
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Lithium dihydrogen phosphate
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Iron is a metal. The structure of iron is described as a lattice of positive ions in a sea of
KATRIN_1 [288]

Answer: 1and 4

Explanation: iron is an element not an alloy. An ionic lattice is not bonded covalently.

6 0
2 years ago
A 41.1 g sample of solid CO2 (dry ice) is added to a container at a temperature of 100 K with a volume of 3.4 L.A. If the contai
marta [7]

Answer:

Approximately 6.81 × 10⁵ Pa.

Assumption: carbon dioxide behaves like an ideal gas.

Explanation:

Look up the relative atomic mass of carbon and oxygen on a modern periodic table:

  • C: 12.011;
  • O: 15.999.

Calculate the molar mass of carbon dioxide \rm CO_2:

M\!\left(\mathrm{CO_2}\right) = 12.011 + 2\times 15.999 = 44.009\; \rm g \cdot mol^{-1}.

Find the number of moles of molecules in that 41.1\;\rm g sample of \rm CO_2:

n = \dfrac{m}{M} = \dfrac{41.1}{44.009} \approx 0.933900\; \rm mol.

If carbon dioxide behaves like an ideal gas, it should satisfy the ideal gas equation when it is inside a container:

P \cdot V = n \cdot R \cdot T,

where

  • P is the pressure inside the container.
  • V is the volume of the container.
  • n is the number of moles of particles (molecules, or atoms in case of noble gases) in the gas.
  • R is the ideal gas constant.
  • T is the absolute temperature of the gas.

Rearrange the equation to find an expression for P, the pressure inside the container.

\displaystyle P = \frac{n \cdot R \cdot T}{V}.

Look up the ideal gas constant in the appropriate units.

R = 8.314 \times 10^3\; \rm L \cdot Pa \cdot K^{-1} \cdot mol^{-1}.

Evaluate the expression for P:

\begin{aligned} P &=\rm \frac{0.933900\; mol \times 8.314 \times 10^3 \; L \cdot Pa \cdot K^{-1} \cdot mol^{-1} \times 298\; K}{3.4\; L} \cr &\approx \rm 6.81\times 10^5\; Pa \end{aligned}.

Apply dimensional analysis to verify the unit of pressure.

4 0
3 years ago
Of the following gases which will have the lowest rate of effusion at a given temperature?A. SO3B. CH4C. NH3D. HBr E. HCl
egoroff_w [7]

Answer: HBr has the lowest rate of effusion at a given temperature.

Explanation: The effusion rate usually increases with increase in temperature because the kinetic energy of the gaseous molecules increases. But it was not true for gases having heavier mass. This was explained by Graham's Law.

Graham's Law states that the rate of effusion of a gas is inversely proportional to the square root of its molecular weight.

(\text{Rate of effusion})_A\propto \frac{1}{\sqrt{\text{Mol. mass}_A}}

We are given different gases with different Molecular masses. The gas having larger Molecular mass will have the lowest rate of effusion.

Mol. Mass of SO_3 = 80 g/mol

Mol. Mass of CH_4 = 16 g/mol

Mol. Mass of NH_3 = 17 g/mol

Mol. Mass of HBr = 81 g/mol

Mol. Mass of HCl = 36 g/mol

As, Mol. mass of HBr is the highest, so its rate of effusion will be the lowest.

6 0
3 years ago
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