The molar Concentration of KMnO₄ is 0.000219 M
Concentration is the abundance of a constituent divided by means of the overall extent of an aggregate. numerous styles of mathematical description may be outstanding: mass awareness, molar awareness, variety concentration, and quantity awareness.
y is absorbance
x is the molar concentration of KMnO_4
y = 4.84E + 03x - 2.26E - 01
0.833 = 4.84 * 10⁺⁰³ x - 2.26 * 10⁻¹
1.059 = 4.84 * 10⁺⁰³ x
X = 0.000219 M
Hence, The molar Concentration of KMnO₄ is 0.000219 M
Learn more about concentration here:-brainly.com/question/14469428
#SPJ9
Answer:
NaNO3 (solubility = 89.0 g/100 g H2O)
Explanation:
The solubility of a specie is the amount of solute that will dissolve in one litre of the solvent. Solubility is usually expressed in units of molarity.
Now let us calculate the molarity of the NaNO3 (solubility = 89.0 g/100 g H2O)
Molar mass of NaNO3= 23+14+3(16)= 85gmol-1
Mass of solute=89.0g
Amount of solute= mass of NaNO3/molar mass of NaNO3
Amount of solute= 89.0g/85.0 gmol-1
= 1.0moles of NaNO3
Note that 100g of water=100cm^3 of water.
If 1.0 moles of NaNO3 dissolve in 100cm^3 or water therefore,
x moles of NaNO3 will dissolve in 1000cm^3 of water
x= 1.0 × 1000/ 100
x= 10.0 moles of NaNO3
Since there is 9.47 x 1021 atoms of copper in 1 gram, and 8.96 grams/cc is the density of copper, then 9.47 x 8.96 =84.85 x 1021 atoms of copper in the one cubic centimeter of copper.
