Answer:
Part A. 1.355 mol/L
Part B. 0.100 mol
Part C. 74.0 mL
Explanation:
Part A.
The molar mass of luminol is 177.16 g/mol, so the number of moles at 18.0 g is:
n = mass/molar mass
n = 18.0/177.16
n = 0.1016 mol
The molarity is the number of moles divided by the volume (0.075 L)
C = 0.1016/0.075
C = 1.355 mol/L
Part B.
The number of moles is the molarity multiplied by the volume, so:
n = 5.00x10⁻² mol/L * 2.00 L
n = 0.100 mol
Part C.
To prepare a solution by dilution, we can use the equation
C1V1 = C2V2
Where C1 is the concentration of the initial (stock) solution, V1 is its volume necessary, C2 is the concentration of the diluted solution, and V2 is its volume.
Thus, C1 = 1.355 M, C2 = 0.05 M, V2 = 2.00 L
1.355V1 = 0.05*2
V1 = 0.074 L
V1 = 74.0 mL
Answer:
0.133 mL
Explanation:
Given data
- Initial concentration (C₁): 15.0 M
- Initial volume (V₁): to be determined
- Final concentration (C₂): 0.001 M
- Final volume (V₂): 2.00 L
We can find the volume of the concentrated solution using the dilution rule.
C₁ × V₁ = C₂ × V₂
V₁ = C₂ × V₂ / C₁
V₁ = 0.001 M × 2.00 L / 15.0 M
V₁ = 1.33 × 10⁻⁴ L = 0.133 mL
1.98 × 10^<span>-11</span><span> J i just took it this is the right awnser</span>
Explanation:
Once blood glucose levels increase, pancreatic insulin migrates into a fat cell via the blood stream. Insulin then binds in the plasma membrane of the cell to an Insulin Receptor (IR). Through autophosphorylation, phosphate groups are then added to the IR, causing GLUT4 molecules to come to the cell's surface.
