Answer:
Step-by-step explanation:
A parallel line will have the same slope as the reference line. In this case, I don't see the "given line" as promised in the question. If it does appear, and it looks like y = 5x + 3, for example, the slope is 5 and the new line will have the same slope.
<h3>
<u>If this slope is correct</u>, we can start the equation for the parallel line that goes through point (-3,2) by starting with:</h3><h3 /><h3>y = 5x + b</h3><h3 /><h3>We need a value of b that forces the line to go through point (-3,2). We can do that by using the given point in the equation and solving for b:</h3><h3>y = 5x + b</h3><h3>2 = 5(-3) + b</h3><h3>b = 17</h3><h3 /><h3>The parallel line to y=5x+3 is</h3><h3>y = 5x + 17</h3><h3 /><h3>See attachment.</h3><h3 /><h3 /><h3 />
Answer: I think it’s D
Step-by-step explanation:
it’s because 8^2 + 13^2 equals 233 and when square rooted equals 15.26 not 20 so no.
A40=a1 +(40-1)r
in this case r is 3 beceause -2+3 will be 1 etc
a40=-2 +39*3
Answer:
I believe its y=5(4)^x
Step-by-step explanation:
The equation is supposed to look like y=ab^x
a is basically where it all starts, so where the y meets the 0
- so the 5 in the y's place meets the 0
b is what you're multiplying by on the y's side, which is by 4 every time
and the x is the exponent and since there is no exponent you leave it as x