Answer:
A sample of 18 is required.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Z-table as such z has a p-value of
.
That is z with a pvalue of
, so Z = 1.88.
Now, find the margin of error M as such
In which
is the standard deviation of the population and n is the size of the sample.
A previous study indicated that the standard deviation was 2.2 days.
This means that ![\sigma = 2.2](https://tex.z-dn.net/?f=%5Csigma%20%3D%202.2)
How large a sample must be selected if the company wants to be 92% confident that the true mean differs from the sample mean by no more than 1 day?
This is n for which M = 1. So
![\sqrt{n} = 1.88*2.2](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D%20%3D%201.88%2A2.2)
![(\sqrt{n})^2 = (1.88*2.2)^2](https://tex.z-dn.net/?f=%28%5Csqrt%7Bn%7D%29%5E2%20%3D%20%281.88%2A2.2%29%5E2)
![n = 17.1](https://tex.z-dn.net/?f=n%20%3D%2017.1)
Rounding up:
A sample of 18 is required.
Answer:
Step-by-step explanation:
- Measure of angle J K H + measure of angle J K L = 180 degrees
True.
- Measure of angle J K L + measure of angle J L K + measure of angle K J L = 180 degrees
True. The sum of all interior angles = 180
- Measure of angle J K H = measure of angle J L K =
Can't tell from info given.
- Measure of angle J K L + measure of angle J L K = 90 degrees
Can't tell from info given.
- Measure of angle K J L = measure of angle K L J
Can't tell from info given.
Answer:
r=28.27 cm aprox
Step-by-step explanation:
Well you know that the area of a circle is A= ![\pi](https://tex.z-dn.net/?f=%5Cpi)
so
2511=![\pi](https://tex.z-dn.net/?f=%5Cpi)
so
=2511/![\pi](https://tex.z-dn.net/?f=%5Cpi)
r=28.27 cm aprox
Okay you have 2 sum unknow lets call them X+Y
so X+Y=33, 4X=108
Get X by it self then plug it in 4X=108
X=-Y+33
4(-y+33)= 108
-4y+132=108 Then subtract the 132
-4y=-24 Y=6 then to find X subtract 33-6=27
Y=6 X=27 if you check it works out