Answer:
Options c and d
Step-by-step explanation:
Given is a graph with period pi.
ii) The graph is discontinuous
iii) x intercepts are say (a) units to the right of y axis and repeats for every interval of pi.
Fix the function
a) y = sinx cannot be this graph because sinx is a continuous graph
b) y =cosx cannot be this graph because cosx is a continuous graph
e) y = sec x is undefined for the range (-1,1) since the given graph is defined in this interval, secx is not answer.
f)y = csc x is undefined for the range (-1,1) since the given graph is defined in this interval, cscx is not answer.
c) y=tanx is a discontinuous graph at x = odd multiples of pi/2
Hence the given graph can be of the form y =- tan (2x+a) which shows reflection over y axis,
d) y = cotx can also be this graph with adjustments for period and horizontal shift.
So answers are c and d
Answer:
y=-2x+5. (4,-3)
Step-by-step explanation:
1) What's being asked in other words is to write a function. So the initial point is (1,3). In x-axis, a translation movement can only be to the right or to the left. Similarly for y-axis the possible movements are shifting up or down. The question says, 3 units right for x-cordinate and 6 units down for y cordinate. So the final point of this translation would be (1+3,3-6) =(4,-3)
2) To write a linear function we need to find out the slope:


y=-2x+5
<u>Proof:</u>
x=1
y=-2(1)+5
y=3 Then (1,3)
x=4
y=-2(4)+5
y=-8+5
y=-3 Then (4,-3)
Answer:
true
Step-by-step explanation:
idek