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WITCHER [35]
3 years ago
8

Lila deposits her earnings from teaching children in a bank account. She has the peace of mind that her money will remain safe i

n the bank. She does not receive any interest from her savings account. She feels that transferring money through checks is unsafe. So she withdraws cash when she wants to lend money to someone.
Mathematics
1 answer:
liberstina [14]3 years ago
6 0

Answer: Lila is incorrect about transferring money through checks.

Step-by-step explanation: If Lila transfers money through checks then she is adding money to her bank account funds and increasing her interests if she leaves the money there for a while.

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A technician is launching fireworks near the event of a show. Of the remaining 11 fireworks, 4 are blue and 7 are red. If she la
SpyIntel [72]

\displaystyle |\Omega|=\binom{11}{6}=\dfrac{11!}{6!5!}=\dfrac{7\cdot8\cdot9\cdot10\cdot11}{2\cdot3\cdot4\cdot5}=462\\ |A|=\binom{4}{2}=\dfrac{4!}{2!2!}=\dfrac{3\cdot4}{2}=6\\\\ P(A)=\dfrac{6}{462}=\dfrac{1}{77}\approx1\%

8 0
3 years ago
Which function is the inverse of f(x)= 3x+5 over 7
Pani-rosa [81]

f(x) = (3x+5)/7

Step 1:

we write f(x) as y

y=(3x+5)/7

Step 2:

switch y by x and x by y

x=(3y+5)/7

Step 3:

solve for y,

x=(3y+5)/7

multiply both sides by 7

7x=3y+5

subtract 5 from left side

3y=7x-5

divide both sides by 3

y= (7x-5)/3

f⁻¹ (x) =(7x-5)/3

8 0
3 years ago
x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco
igomit [66]

Answer:

x=-cos(t)+2sin(t)

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

Will have a characteristic equation of the form:

a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0

Where solutions r_1,r_2...,r_n are the roots from which the general solution can be found.

For real roots the solution is given by:

y(t)=c_1e^{r_1t} +c_2e^{r_2t}

For real repeated roots the solution is given by:

y(t)=c_1e^{rt} +c_2te^{rt}

For complex roots the solution is given by:

y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)

Where:

r_1_,_2=\lambda \pm \mu i

Let's find the solution for x''+x=0 using the previous information:

The characteristic equation is:

r^{2} +1=0

So, the roots are given by:

r_1_,_2=0\pm \sqrt{-1} =\pm i

Therefore, the solution is:

x(t)=c_1cos(t)+c_2sin(t)

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of x(t) in order to find the constants c_1 and c_2:

x'(t)=-c_1sin(t)+c_2cos(t)

Evaluating the initial conditions:

x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1

And

x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2

Now we have found the value of the constants, the solution of the second-order IVP is:

x=-cos(t)+2sin(t)

3 0
3 years ago
A scale on a map shows that 2.5 centimeters represent 15 kilometers.
MrRissso [65]

Answer:

cm for centimeters, km for kilometers.

 

If 2.5cm → 15 km, then

 17.5 cm → x km

 

x= (15km*17.5cm)/(2.5cm)=105 km

Step-by-step explanation:

4 0
2 years ago
Margret works at a bakery. She is paid $300 every week plus $12 an hour for any
vivado [14]

Answer:

300+12x=$450

Step-by-step explanation:

8 0
3 years ago
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