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stepladder [879]
3 years ago
14

When working with vectors, you will often see right triangles. What are the consistent properties of these triangles?

Physics
1 answer:
german3 years ago
4 0

Answer:

a) and c)

Explanation:

  • Any vector can be expressed as a vector sum of its x- and -y components, as follows:

        v = vₓ* x + vy* y

  • where vₓ = x- component, x= unit vector in the x direction, vy = y-component, y = unit vector in the y direction.
  • If we add the components graphically, using the head-to-tail method, it will be defined a right triangle, being the vector sum of both components (the vector itself) the hypotenuse of the triangle.
  • As both components are perpendicular, they will be always lined up with the x- and y- axes.
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What must the charge (sign and magnitude) of a 1.65 gg particle be for it to remain balanced against gravity when placed in a do
balandron [24]

Answer:

Charge, q=2.52\times 10^{-5}\ C and it is negative.

Explanation:

Given that,

Mass of the charge, m=1.65\ g=1.65\times 10^{-3}\ kg

Electric field, E = 640 N/C

To find,

Charge

Solution,

The electric force and the force of gravity are balanced in the electric field. It is given by :

qE=mg

q=\dfrac{mg}{E}

q=\dfrac{1.65\times 10^{-3}\times 9.8}{640}

q=2.52\times 10^{-5}\ C

Since, the electric field is in downward direction. The force must be upward direction s that the charge is negative.    

5 0
4 years ago
Read 2 more answers
For each of the cases listed below, decide whether or not the motion described is an example of acceleration: (T/F)
scoundrel [369]

Answer:

1. True

2. True

3. False

4. False

5. True

6. False

Explanation:

Acceleration: It refers to the change in velocity/speed of an object with respect to time. When the speed increases with time we call it acceleration and when its decreases it is called as deceleration.  Let us analyze each instance individually:

1. When roller coaster starts to roll down the track its speed will increase with time. That means it is accelerating.

2. When the ball reaches at the peak of its trajectory, it comes to a stop for a fraction of a second that means it decelerates.

3. Since the velocity remains constant there is no acceleration.

4. Since the speed is no changing with time, there is no acceleration.

5. Since the moving plane comes to a stop, it is a case of deceleration.

6. Since the truck is moving at a constant speed so the acceleration is zero.

8 0
4 years ago
Which is the correct free body diagram for this sutuation?<br>​
marshall27 [118]

I think C because it's the only one with a an angle T of 30° (The string)

8 0
4 years ago
When the drivers pass each other, the driver of the red car is to toss a package of contraband to the other driver. To catch the
Brrunno [24]

Answer:

D=387.28m

Explanation:

At the moment where the toss is made X_R = X_G, so we need both equations:

For the red car:

X_R=\frac{a_R*t^2}{2}   With initial speed of 0 and acceleration of 6.12m/s^2.

For the green car:

X_G=Xo + V_G*t   With V_G = 60km/h*\frac{1000m}{1km} * \frac{1h}{3600s} = 16.66m/s   and Xo = 200m

Since both positions will be the same:

\frac{a_R*t^2}{2}=Xo+V_G*t   Solving for t:

t1 = -5.8s  and   t1 =11.25s

Replacing t = 11.25 on either equation to find the displacement:

D = X_R = \frac{a_R*t^2}{2} = 387.28m

3 0
4 years ago
The amplitude of oscillation is the maximum distance between the oscillating weight and the equilibrium position. Determine the
Eva8 [605]

Answer:

The frequency does not depend on the amplitude for any (ideal) mechanical or electromagnetic waves.

In electromagnetism we have that the relation is:

Velocity = wavelenght*frequency.

So the amplitude of the wave does not have any effect here.

For a mechanical system like an harmonic oscillator (that can be used to describe almost any oscillating system), we have that the frequency is:  

f = (1/2*pi)*√(k/m)

Where m is the mass and k is the constant of the spring, again, you can see that the frequency only depends on the physical properties of the system, and no in how much you displace it from the equilibrium position.

This happens because as more you displace the mass from the equilibrium position, more will be the force acting on the mass, so while the "path" that the mass has to travel is bigger, the mas moves faster, so the frequency remains unaffected.

5 0
3 years ago
Read 2 more answers
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