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stepladder [879]

3 years ago

14

When working with vectors, you will often see right triangles. What are the consistent properties of these triangles?

1 answer:

german3 years ago

4 0

Answer:

a) and c)

Explanation:

Any vector can be expressed as a vector sum of its x- and -y components, as follows:

v = vₓ* x + vy* y

where vₓ = x- component, x= unit vector in the x direction, vy = y-component, y = unit vector in the y direction.

If we add the components graphically, using the head-to-tail method, it will be defined a right triangle, being the vector sum of both components (the vector itself) the hypotenuse of the triangle.
As both components are perpendicular, they will be always lined up with the x- and y- axes.

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Two long, straight wires are parallel and 16 cm apart. One carries a current of 2.9 A, the other a current of 5.7 A. (a) If the

Mnenie [13.5K]

Explanation:

Given that,

Distance between two long wires, d = 16 cm = 0.16 m

Current in one wire, $I_1=2.9\ A$

Current in wire 2, $I_2=5.7\ A$

The magnetic force per unit length of one wire on the other is given by the following expression as :

$\dfrac{F}{l}=\dfrac{\mu_o I_1I_2}{2\pi d}$

$\dfrac{F}{l}=\dfrac{4\pi \times 10^{-7}\times 2.9\times 5.7}{2\pi \times 0.16}$

$\dfrac{F}{l}=2.06\times 10^{-5}\ N/m$

The current is flowing in opposite direction, the magnetic force acting on it is repulsive. Hence, this is the required solution.

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4 years ago

What force does the laser beam exert on a completely absorbing target?

saw5 [17]

You would have to use the partition force to laaser beam expert on a completely absorbing target

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3 years ago

The weight of an object is the same on two different planets. The mass of planet A is only sixty percent that of planet B. Find

natka813 [3]

Answer:

0.775

Explanation:

The weight of an object on a planet is equal to the gravitational force exerted by the planet on the object:

$F=G\frac{Mm}{R^2}$

where

G is the gravitational constant

M is the mass of the planet

m is the mass of the object

R is the radius of the planet

For planet A, the weight of the object is

$F_A=G\frac{M_Am}{R_A^2}$

For planet B,

$F_B=G\frac{M_Bm}{R_B^2}$

We also know that the weight of the object on the two planets is the same, so

$F_A = F_B$

So we can write

$G\frac{M_Am}{R_A^2} = G\frac{M_Bm}{R_B^2}$

We also know that the mass of planet A is only sixty percent that of planet B, so

$M_A = 0.60 M_B$

Substituting,

$G\frac{0.60 M_Bm}{R_A^2} = G\frac{M_Bm}{R_B^2}$

Now we can elimanate G, MB and m from the equation, and we get

$\frac{0.60}{R_A^2}=\frac{1}{R_B^2}$

So the ratio between the radii of the two planets is

$\frac{R_A}{R_B}=\sqrt{0.60}=0.775$

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Dennis_Churaev [7]

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