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stepladder [879]
3 years ago
14

When working with vectors, you will often see right triangles. What are the consistent properties of these triangles?

Physics
1 answer:
german3 years ago
4 0

Answer:

a) and c)

Explanation:

  • Any vector can be expressed as a vector sum of its x- and -y components, as follows:

        v = vₓ* x + vy* y

  • where vₓ = x- component, x= unit vector in the x direction, vy = y-component, y = unit vector in the y direction.
  • If we add the components graphically, using the head-to-tail method, it will be defined a right triangle, being the vector sum of both components (the vector itself) the hypotenuse of the triangle.
  • As both components are perpendicular, they will be always lined up with the x- and y- axes.
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how fast is a ball going when it hits the ground after being dropped from a height of 16m the acceleration of gravity is 9.8
Aneli [31]

Answer:

17.7 m/s

Explanation:

Given:

y₀ = 0 m

y = 16 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: v

v² = v₀² + 2a (y − y₀)

v² = (0 m/s)² + 2 (9.8 m/s²) (16 m − 0 m)

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The ball is moving at a speed of 17.7 m/s when it hits the ground.

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3 years ago
Pls answer need help
igomit [66]

Answer:

See below

Explanation:

Find the NET forces on the objects

A  20==>

B    0

C  30==>

D  15==>    

So biggest accel = C because it has the most force acting on it

 next is A because it has the next biggest force

    next is  D        then    B ...B has no net force acting on it  

6 0
2 years ago
A single slit 1.4 mmmm wide is illuminated by 460-nmnm light. Part A What is the width of the central maximum (in cmcm ) in the
mamaluj [8]

Answer:

<h2> 1.643*10⁻⁴cm</h2>

Explanation:

In a single slit experiment, the distance on a screen from the centre point is expressed as y = \frac{\delta m \lambda d}{a} where;

\delta m is the first two diffraction minima = 1

\lambda is light wavelength

d is the distance of diffraction pattern from the screen

a is the width of the slit

Given \lambda = 460-nm = 460*10⁻⁹m

d = 5.0mm = 5*10⁻³m

a = 1.4mm = 1.4*10⁻³m

Substituting this values into the formula above to get width of the central maximum y;

y = 1*460*10⁻⁹ * 5*10⁻³/1.4*10⁻³

y = 2300*10⁻¹²/1.4*10⁻³

y = 1642.86*10⁻⁹

y = 1.643*10⁻⁶m

Converting the final value to cm,

since 100cm = 1m

x = 1.643*10⁻⁶m

x = 1.643*10⁻⁶ * 100

x = 1.643*10⁻⁴cm

Hence, the width of the central maximum in the diffraction pattern on a screen 5.0 mm away is  1.643*10⁻⁴cm

3 0
3 years ago
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